Answer:
See the answers below.
Explanation:
The cost of energy can be calculated by multiplying each given value, a dimensional analysis must be taken into account in order to calculate the total value of the cost in Rs.
![Cost=0.350[kW]*12[\frac{hr}{1day}]*30[days]*4.5[\frac{Rs}{kW*hr} ]=567[Rs]](https://tex.z-dn.net/?f=Cost%3D0.350%5BkW%5D%2A12%5B%5Cfrac%7Bhr%7D%7B1day%7D%5D%2A30%5Bdays%5D%2A4.5%5B%5Cfrac%7BRs%7D%7BkW%2Ahr%7D%20%5D%3D567%5BRs%5D)
The fuse can be calculated by knowing the amperage.
where:
P = power = 350 [W]
V = voltage = 240 [V]
I = amperage [amp]
Now clearing I from the equation above:
![I=P/V\\I=350/240\\I=1.458[amp]](https://tex.z-dn.net/?f=I%3DP%2FV%5C%5CI%3D350%2F240%5C%5CI%3D1.458%5Bamp%5D)
The fuse should be larger than the current of the circuit, i.e. about 2 [amp]
The answer is C. Watson and Crick developed the Double Helix model seen in the diagram.
For a white dwarf star<span> to become explosively active, </span>the gap<span> between the dwarf </span>and therefore the<span> companion </span>should<span> be </span>sufficiently little<span> that the white dwarf's </span>force field will<span> pull matter </span>aloof from<span> the surface of the companion. </span>because of<span> the rotation of the </span>positional representation system<span>, the matter flowing through the mass-transfer stream from the companion star forms a </span>flat <span>disk, </span>known as associate degree<span> accretion disk, </span>that<span> orbits </span>round the white dwarf star<span>.</span>
Before any calculations, we need to determine first the crystal structure of the lead metal. From literature, the lead metal assumes an FCC structure. So, it would have 4 atoms per units cell where the three atoms is the sum of all the portion of an atoms in each face of the cell and the 1 atom is the sum of all the portion of the corner atoms. The volume of the unit cell is equal to the edge length raise to the power three or V = a^3. The edge length can be calculated from the radius of the atoms by the pythagorean theorem. We do as follows:
V = a^3
a^2 + a^2 = (4r)^2
2a^2 = (4r)^2
a = 2r
V = (2r)^3
V = 16r^3
V = 16 (0.175x10^-9)^3
V = 1.21 x 10^-28 m^3
The ratio of the primary turns to the secondary turns is 1/3
The correct answer to the question is Option A. 1/3
From the question given above, the following data were obtained:
- Primary turn (Nₚ) = 225 turns
- Secondary turn (Nᵣ) = 675 turns
- Ratio of primary to secondary =?
Ratio = Nₚ/Nᵣ
Nₚ/Nᵣ = 225 / 675
Nₚ/Nᵣ = 1/3
Therefore, the ratio of the primary turns to the secondary turns is 1/3
Complete question:
See attached photo
Learn more about transformer: brainly.com/question/17921540
