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3 years ago

CAN SOMEONE HELP ME

Physics

1 answer:

Mashcka [7]3 years ago

7 0

Explanation:

1) CHEMICAL energy from gas, oil, or coal provides

2) HEAT energy to water to produce steam. A turbine changes the energy of the steam into the

3) MECHANICAL energy of the rotating turbine and generator. The generator converts the energy into

4) ELECTRIC energy. The lamp is an energy converter changing,

5) ELECTRIC energy to

6) LIGHT energy and

7) HEAT energy

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Identify which type of source is being described.

frez [133]

Answer:

Primary, secondary

Explanation:

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3 years ago

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A charge of -3.02 μC is fixed in place. From a horizontal distance of 0.0377 m, a particle of mass 9.43 x 10^-3 kg and charge -9

Andreyy89

Answer:

$d = 0.0306 m$

Explanation:

Here we know that for the given system of charge we have no loss of energy as there is no friction force on it

So we will have

$U + K = constant$

$\frac{kq_1q_2}{r_1} + \frac{1}{2}mv_1^2 = \frac{kq_1q_2}{r_2} + \frac{1}{2}mv_2^2$

now we know when particle will reach the closest distance then due to electrostatic repulsion the speed will become zero.

So we have

$\frac{(9 \times 10^9)(3.02 \mu C)(9.78 \mu C)}{0.0377} + \frac{1}{2}(9.43 \times 10^{-3})(80.4)^2 = \frac{(9 \times 10^9)(3.02 \mu C)(9.78 \mu C)}{r} + 0$

$7.05 + 30.5 = \frac{0.266}{r}$

$r = 7.08 \times 10^{-3} m$

so distance moved by the particle is given as

$d = r_1 - r_2$

$d = 0.0377 - 0.00708$

$d = 0.0306 m$

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3 years ago

Which statement best describes an atom? (1 point) protons and neutrons grouped in a specific pattern protons and electrons sprea

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A group of protons and neutrons surrounded by electrons

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Match the player positions with his or her job on the court.

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3 years ago

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a shell fired from a cannon at 60 ° from horizontal strikes a target 20m high at a distance 80m. Calculate the initial velocity

stich3 [128]

consider the motion along the X-direction

X = horizontal displacement = 80 m

$V_{ox}$ = initial velocity along the x-direction = v Cos60

t = time of travel

using the equation

X = $V_{ox}$ t

80 = (v Cos60) (t)

t = 160/v eq-1

consider the motion in vertical direction :

Y = vertical displacement = 20 m

$V_{oy}$ = initial velocity in Y-direction = v Sin60

a = acceleration = - 9.8 m/s²

t = time of travel = 160/v

using the equation

Y = $V_{oy}$ t + (0.5) a t²

20 = (v Sin60) (160/v) + (0.5) (- 9.8) (160/v)²

v = 32.5 m/s

4 0

3 years ago

CAN SOMEONE HELP ME​

CAN SOMEONE HELP ME