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const2013 [10]
3 years ago
13

Two types of reactions occur when baking soda and vinegar combine. The first is a double replacement reaction. Write a balanced

equation for this reaction. Please balance both equations.
__Na(HCO₃) + __H(C2H₃O₂) → __Na(C₂H₃O₂) + __H₂CO₃
__H₂CO₃ → __H₂O + __CO₂
Chemistry
2 answers:
Vsevolod [243]3 years ago
6 0
<span>The chemical equation for the Vinegar & Baking Soda reaction is: NaHCO3(s) + CH3COOH(l) → CO2(g) + H2O(l) + Na+(aq) + CH3COO-(aq) with s = solid, l = liquid, g = gas, aq = aqueous or in water solution Another reaction is: NaHCO3 + HC2H3O2 → NaC2H3O2 + H2O + CO2 The chemical reaction actually occurs in two steps. First, there is double displacement reaction in which acetic acid in vinegar reacts with sodium bicarbonate to form sodium acetate and carbonic acid: NaHCO3 + HC2H3O2 → NaC2H3O2 + H2CO3 Then,Carbonic acid is unstable and undergoes a decomposition reaction to produce the carbon dioxide gas: H2CO3 → H2O + CO2</span>
e-lub [12.9K]3 years ago
5 0

1) Balanced chemical reaction:

<u>1</u>Na(HCO₃) + <u>1</u>H(C2H₃O₂) → <u>1</u>Na(C₂H₃O₂) + <u>1</u>H₂CO₃.

Double replacement reactions (double displacement or metathesis reactions), two ionic compounds are exchanged, making two new compounds.

2) Balanced chemical reaction: <u>1</u>H₂CO₃ → <u>1</u>CO₂ + <u>1</u>H₂O.

H₂CO₃ is carbonic acid.

CO₂ is carbon (IV) oxide or carbon dioxide.

Chemical decomposition is the separation of a single chemical compound (in this example carbonic acid) into its two or more simpler compounds (in this example water and carbon dioxide).

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Methanol and butanol are alcohols. Alcohols have the same_______________ as alkanes and the __________ identifies the compound a
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Explanation:

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7 0
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You are given solutions of hcl and naoh and must determine their concentrations. you use 27.5 ml of naoh to titrate 100.0 ml of
Dafna1 [17]
1) Start by standardizing the solution of NaOH by using the solution of H2SO4 whose concentration is known.

2) Equation:

2Na OH + H2SO4 --> Na2 SO4 + 2H2O

3) molar ratios

2 mol NaOH : 1 mol H2SO4

4) Number of moles of H2SO4 in 50.0 ml of 0.0782 M solution

M = n / V => n = M*V = 0.0782 M * 0.050 l = 0.00391 mol H2SO4

5) Number of moles of NaOH

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6) Concentration of the solution of NaOH

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7) Standardize the solution of HCl

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8) Molar ratios

1 mol NaOH : 1 mol HCl

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M = n / V => n = M * V = 0.425 M * 0.0275 l = 0.01169 moles NaOH

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1 mol HCl / 1mol NaOH * 0.01169 mol NaOH = 0.01169 mol HCl

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Rounded to 3 significant figures = 0.117 M

Answers:

[NaOH] = 0.425 M
[HCl] = 0.117 M
3 0
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Bas_tet [7]

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2.A theory requires experimentation under various conditions. A law has no such requirements.
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Hope this helps:)


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