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2 years ago

8

Calculate moles of oxygen atoms in 0.68mol of KMnO4

1 answer:

Dominik [7]2 years ago

6 0

Alright, so that means we have 0.68 mol of the compound

For each 1 mol of the compound, we have 4*1 oxygens (because there are four oxygens in the formula)
Therefore for each 0.68 mol of the compound, we have 4*0.68 moles of oxygen!

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How Many Atoms Are In 356.13 Grams Of Sn

s344n2d4d5 [400]

<span>There are three atoms of Sn (Stannous or Tin) in</span> 356.13 g of Sn.

<span>One atom of Sn has the atomic mass (m</span>ₐ<span>) of </span>118,71u which means:

356.13/118.71=3 atoms of Sn

The mass number (symbol A) also called atomic mass number or nucleon number is the total number of protons and neutrons in an atomic nucleus. It determines the atomic mass of atoms and it is in the periodic table.

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2 years ago

A chemist must prepare 300.0mL of nitric acid solution with a pH of 0.70 at 25°C. He will do this in three steps: Fill a 300.0mL

d1i1m1o1n [39]

<u>Answer:</u> The volume of concentrated solution required is 9.95 mL

<u>Explanation:</u>

To calculate the pH of the solution, we use the equation:

$pH=-\log[H^+]$

We are given:

pH = 0.70

Putting values in above equation, we get:

$0.70=-\log[H^+]$

$[H^+]=10^{-0.70}=0.199M$

1 mole of nitric acid produces 1 mole of hydrogen ions and 1 mole of nitrate ions.

Molarity of nitric acid = 0.199 M

To calculate the volume of the concentrated solution, we use the equation:

$M_1V_1=M_2V_2$

where,

$M_1\text{ and }V_1$ are the molarity and volume of the concentrated nitric acid solution

$M_2\text{ and }V_2$ are the molarity and volume of diluted nitric acid solution

We are given:

$M_1=7.0M\\V_1=?mL\\M_2=0.199M\\V_2=350mL$

Putting values in above equation, we get:

$7.0\times V_1=0.199\times 350.0\\\\V_1=\frac{0.199\times 350}{7.0}=9.95mL$

Hence, the volume of concentrated solution required is 9.95 mL

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2 years ago

How many of the planets have an orbital period of less than one Earth year?

GrogVix [38]

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2 years ago

If the specific heat of water is 4.186 kJ/kg∙°C, how much heat is required to increase the temperature of 1.2 kg of water from 2

PIT_PIT [208]

This<span> will require'' </span>266.9kJ''<span> of heat energy

</span>

To calculate the energy required to raise the temperature of any given substance, here's what you require:

The mass of the material, <span>m</span>

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2 years ago

Calculate the percent by volume of a solution that has 75 mL of solute dissolved in 375 mL of solution. Show your work and round

Mandarinka [93]

Answer:

The answer is 20 % V/V

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3 years ago