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Lina20 [59]
3 years ago
8

When 0.7521 g of benzoic acid was burned in a calorimeter, a temperature rise of 3.60°C was observed. What is the heat capacity

of the bomb calorimeter? The heat of combustion of benzoic
Chemistry
1 answer:
Annette [7]3 years ago
7 0
Answer : S=1.34 KJ

The complete question is -

<span>When 0.7521 g of benzoic was burned in a calorimeter containing 1000 g of water, a temperature rise of 3.60C was observed. What is the heat capacity of the bomb calorimeter, excluding water? The specific heat of water is 4.184 J/g-C and the heat of combustion of benzoic acid is 26.42 kJ/g. 
</span>
On using the formula of Q_{rxn} = mSt, where m is mass of benzoic acid and S is specific heat and t is temperature, we ignore S at this stage.

on solving we get,  Q_{rxn} = 0.7521 X 26.42 = 19.870 KJ

We know, Q_{rxn} =Q_{calorimeter} + Q_{water}

Sp. heat of water is 4.184 J,

Here Q_{water} = 1000 X 4.184 X 3.6 = 15062.4 J

on multiplying Q_{rxn} X 1000 to convert into J = <span>19870.42 J

on substituting the values we get, </span>19870.482 = 15062.4 + Q_{calorimeter}, 
hence, Q_{calorimeter}= <span>4808.082,

</span>Substituting in  Q_{rxn} , we get, 4808.082=St ...(ignoring mass as we changed it to J)

t = 3.6, hence we get, S=1335 J/C on dividing by 1000 we get, S=1.34 KJ

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what volume of a 0.155 M calcium hydroxide solution is required to neutralize 28.8 mL of a 0.106 M nitric acid?​
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Answer:

9.85mL

Explanation:

First, let us write a balanced equation for the reaction. This is illustrated below:

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From the balanced equation above,

nA (mole of the acid) = 2

nB (mole of the base) = 1

Data obtained from the question include:

Vb (volume of the base) =?

Mb (Molarity of base) = 0.155 M

Va (volume of the acid) = 28.8 mL

Ma (Molarity of acid) = 0.106 M

Using MaVa/MbVb = nA/nB, the volume of calcium hydroxide (i.e the base) can be obtain as follow:

MaVa/MbVb = nA/nB

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Cross multiply to express in linear form as shown below:

2 x 0.155 x Vb = 0.106 x 28.8

Divide both side by 2 x 0.155

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7 0
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