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Zina [86]
3 years ago
7

How many moles of hcl are required to neutralize aqueous solutions of these bases? 0.03 mol koh?

Chemistry
1 answer:
oksano4ka [1.4K]3 years ago
5 0
 The  moles  of  HCl    are  required  to  neutralized    aqueous     solution     of  the   0.03  KoH

KOH  +  HCl  =  KCl  +   H2O


by   use  mole  ratio  between  KOH   to   HCl    which  is    1:1    the  moles    Of  HCl  is  also      0.03  moles
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A 15.0 mL urine from a dehydrated patient has a density of 1.019g/mL. What is the mass of the sample, reported in mg?
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Answer:

Mass of sample in mg = 15,285 mg

Explanation:

Given:

Volume of urine sample = 15 ml

Density of sample = 1.019 g/ml

FInd:

Mass of sample in mg

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Mass = density x volume

Mass of sample in mg = Volume of urine sample x Density of sample

Mass of sample in mg = 1.019 x 15

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Se ha añadido un evaporador para una alimentación de 11500 kg/dia de zumo de pomelo de forma que evapore 3000 kg/dia de agua por
mamaluj [8]

Answer:

37 %.

Explanation:

¡Hola!

En este caso, para el problema descrito, conocemos la corriente de entrada y la de salida del agua, por lo que podemos obtener el flujo de la corriente que contiene el zumo a la salida una vez el agua fue evaporada:

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Luego, por medio de un balance de zumo de limón en el evaporador en el cual la cantidad que entra es igual a la que sale con sus respectivas concentraciones:

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Como la concentración del zumo a la salida es del 50 % (0.50), la de entrada es:

x_z^{entra}=\frac{x_z^{sale}*8500kg/dia}{11500kg/dia} =\frac{0.50*8500kg/dia}{11500 kg/dia}\\ \\x_z^{entra}=0.37

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¡Saludos!

6 0
3 years ago
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