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Shtirlitz [24]
3 years ago
11

A barber shop produces 192 haircuts a day. each barber in the shop works 8 hours per day and produces the same number of haircut

s per hour. if the shop's productivity is 2 haircuts per hour of labor, then how many barbers does the shop employ?
a. 16
b. 8
c. none of the above is correct.
d. 12
Mathematics
1 answer:
kenny6666 [7]3 years ago
5 0
The number of barbers to employ is 12
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specific park is rectangular-shaped and has a 7-mile perimeter. The length is 4 times the width. What are the dimensions of the
denis23 [38]
This is an algabraic problem, so we would use variables:
Length=x
Width=y
The length is four times the width, so
x=4y
Since the equation for perimeter is P= 2(x+y), you would instead substitute 4y for x, and 7 for the perimeter.
7=2(4y+y)
Simplify.
7=2(5y)
7=10y
y=7/10
Since y is 7/10, you would substitute 7/10 into the equation x=4y.
x=4(7/10)
x=14/5
So, the dimensions are 7/10 x 14/5.
Hope this helps!
7 0
3 years ago
HELP ASAP PLSSS IM DESPERATE!!!! HELP IN 5MINS PLS!!!
Evgen [1.6K]

Answer:

angle v and angle w,  

angle x and angle y

(the first one)

6 0
3 years ago
A car traveled on the highway at 65 miles per hour for 45 minutes. What distance did the car travel?
daser333 [38]

i think its 52 miles.

the fraction of the time is 4/5 which is .8 so

65 * .8 = 52

i hope this helps :)

3 0
3 years ago
What is the surface area of the box if it is scaled up by the factor of 10 and the surface area is 16in
algol [13]
If each linear dimension is scaled by a factor of 10, then the area is scaled by a factor of 100. This is because 10^2 = 10*10 = 100. Consider a 3x3 square with area of 9. If we scaled the square by a linear factor of 10 then it's now a 30x30 square with area 900. The ratio of those two areas is 900/9 = 100. This example shows how the area is 100 times larger.

Going back to the problem at hand, we have the initial surface area of 16 square inches. The box is scaled up so that each dimension is 10 times larger, so the new surface area is 100 times what it used to be

New surface area = 100*(old surface area)
new surface area = 100*16
new surface area = 1600

Final Answer: 1600 square inches

3 0
2 years ago
A random sample of 25 ACME employees showed the average number of vacation days taken during the year is 18.3 days with a standa
Norma-Jean [14]

Answer:

a) Null hypothesis:\mu \leq 15  

Alternative hypothesis:\mu > 15  

b) df=n-1=25-1=24  

For this case the p value is given p_v = 0.0392

If we compare the p value and the significance level given \alpha=0.05 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, so we can conclude that the true mean is higher than 15 at 5% of signficance.  

c) Type I error, also known as a “false positive” is the error of rejecting a null  hypothesis when it is actually true. Can be interpreted as the error of no reject an  alternative hypothesis when the results can be  attributed not to the reality.

So for this case a type I of error would be reject the hypothesis that the true mean is less or equal than 15 and is actually true.

Step-by-step explanation:

Data given and notation  

\bar X=18.3 represent the sample mean

s=3.72 represent the sample standard deviation

n=25 sample size  

\mu_o =15 represent the value that we want to test

\alpha=0.05 represent the significance level for the hypothesis test.  

t would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

Part a: State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the true mean for vacation days is higher than 15, the system of hypothesis would be:  

Null hypothesis:\mu \leq 15  

Alternative hypothesis:\mu > 15  

If we analyze the size for the sample is < 30 and we don't know the population deviation so is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:  

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}  (1)  

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

Part b: P-value  and conclusion

The first step is calculate the degrees of freedom, on this case:  

df=n-1=25-1=24  

For this case the p value is given p_v = 0.0392

Conclusion  

If we compare the p value and the significance level given \alpha=0.05 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, so we can conclude that the true mean is higher than 15 at 5% of signficance.  

Part c

Type I error, also known as a “false positive” is the error of rejecting a null  hypothesis when it is actually true. Can be interpreted as the error of no reject an  alternative hypothesis when the results can be  attributed not to the reality.

So for this case a type I of error would be reject the hypothesis that the true mean is less or equal than 15 and is actually true.

3 0
2 years ago
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