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oksano4ka [1.4K]
2 years ago
14

Hellppppp&/&/&/&//&/&/&/&/&& will give brainiest

Physics
1 answer:
Komok [63]2 years ago
3 0

Explanation:

i really didn't understand the question

im soo so sorry

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Calculate the distance travel if it accelerates from 0 to 27.8 meters per second in 2.5 seconds
luda_lava [24]

The distance travel is 69.5 meters.

<u>Explanation:</u>

Given datas are as follows

Speed = 27.8 meters / second

Time = 2.5 seconds

The formula to calculate the speed using distance and time is

Speed = Distance ÷ Time (units)

Then Distance = Speed × Time (units)

Distance = (27.8 × 2.5) meters          

Distance = 69.50 meters

Therefore the distance travelled is 69.50 meters.

8 0
3 years ago
in a circuit, where do electric charges go once they have left the voltage source and traveled along the wires?
S_A_V [24]
In an electric circuit, the free electrons are moving around. Since equal charges repel and opposite charges attract, the electrons move from the negatively charged to the positively charged pole of the voltage source.
7 0
2 years ago
What is the difference between obtaining knowledge from a controlled experiment versus other forms of scientific investigation?
solong [7]

Answer:

Any scientific investigation in its simplest form involves collecting information, while a controlled experiment is a tightly controlled investigation that tests a hypothesis.

Explanation:

All the scientific investigations start with a particular question. The question decides what type of investigation should research take. A controlled experiment is an investigation which allows a particular variable to change and all other variable controlled to remain constant to see the effect on dependent variable to test a particular hypothesis while other types of investigations are used to increase the knowledge or information about the particular research subject.

6 0
3 years ago
Find the distance covered by a car in 10 second, if it is moving at the speed of 20m/s​
labwork [276]

Answer:

solution

we know that .

s=ut+½at²

now, putting the values in the second equation of motion ,

we get,

S=20×10+1/2×(10)²

S=200+1×100

S=200+100

S=300m

the distance covered by given body or object in 10 seconds is 300 m.

8 0
3 years ago
A shearing of 50N is applied to an aluminum rod with a length of 10m a cross sectional area of 1.0×10-5 and a shear modulus of 2
slega [8]

Answer:

0.002 m or 2 mm

Explanation:

Given that:

Force, F = 50N

Area = 1 * 10^-5

Length, L = 10m

Shear modulus, = 2.5 * 10^10

Using the relation ;

D = (50 ÷ 1*10^-5) ÷ (2.5 * 10^10 ÷ 10)

D = 5000000 ÷ 2.5 * 10^9

D = 5 * 10^6 ÷ 2.5 * 10^9

D = (5/2.5) * 10^(6-9)

D = 2 * 10^-3

D = 0.002 m

1m = 1000 mm

0.002m = (1000 * 0.002) = 2 mm

7 0
3 years ago
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