1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
DanielleElmas [232]
4 years ago
8

Remembering that Force = mass x acceleration. A Football player kicks a ball with a mass of 0.42 kg. The average acceleration of

the football was 14.8 m/s^2. How much force did the kicker supply to the football?
A) 35.24 m/s^2

B) 6.22 N

C) 35.24 N

D) 6.22 m/s^2
Physics
1 answer:
Anna35 [415]4 years ago
6 0

B) 6.22 N

<em>Is your answer hun! have a great day:3</em>

You might be interested in
Physics students study a piano being pulled across a room on a rug. They know that when it is at rest, it experiences a gravitat
Vanyuwa [196]
The static frictional force is greater than the kinetic frictional force, so the static frictional force is greater than 1200 N.
5 0
4 years ago
Read 2 more answers
What does Newton's 2nd Law explain?
kow [346]

Answer:

C. Why you must push harder to move a car farther.

Explanation:

Newton's Second Law of Motion states that the acceleration of a physical object is directly proportional to the net force acting on the physical object and inversely proportional to its mass.

Mathematically, it is given by the formula;

Acceleration = \frac {Force}{mass}

Hence, Newton's 2nd Law explains why you must push harder to move a car farther because of its mass. Thus, it is important to increase the force that the engine provides and decrease the mass of the car.

6 0
3 years ago
a 1-kg discus is thrown with a velocity of 19 m/s at an angle of 35 degrees from the vertical direction. calculate the vertical
nlexa [21]

Answer:

Vx =  10.9 m/s ,  Vy = 15.6 m/s

Explanation:

Given velocity V= 19 m/s

the angle 35 ° is taken from Y-axis so the angle with x-axis will be 90°-35° = 55°

θ = 55°

to Find Vx = ? and Vy= ?

Vx = V cos θ

Vx = 19 m/s  × cos 55°

Vx =  10.9 m/s

Vx = V sin θ

Vy = 19 m/s  × sin 55°

Vy = 15.6 m/s

6 0
3 years ago
Read 2 more answers
It is friction that provides the force for a car to accelerate, so for high-performance cars the factor that limits acceleration
bearhunter [10]

Answer:

About 12 seconds

Explanation:

6 0
3 years ago
A 58.0-kg projectile is fired at an angle of 30.0° above the horizontal with an initial speed of 140 m/s from the top of a cliff
strojnjashka [21]

(a) 6.43\cdot 10^5 J

The total mechanical energy of the projectile at the beginning is the sum of the initial kinetic energy (K) and potential energy (U):

E=K+U

The initial kinetic energy is:

K=\frac{1}{2}mv^2

where m = 58.0 kg is the mass of the projectile and v=140 m/s is the initial speed. Substituting,

K=\frac{1}{2}(58 kg)(140 m/s)^2=5.68\cdot 10^5 J

The initial potential energy is given by

U=mgh

where g=9.8 m/s^2 is the gravitational acceleration and h=132 m is the height of the cliff. Substituting,

U=(58.0 kg)(9.8 m/s^2)(132 m)=7.5\cdot 10^4 J

So, the initial mechanical energy is

E=K+U=5.68\cdot 10^5 J+7.5\cdot 10^4 J=6.43\cdot 10^5 J

(b) -1.67 \cdot 10^5 J

We need to calculate the total mechanical energy of the projectile when it reaches its maximum height of y=336 m, where it is travelling at a speed of v=99.2 m/s.

The kinetic energy is

K=\frac{1}{2}(58 kg)(99.2 m/s)^2=2.85\cdot 10^5 J

while the potential energy is

U=(58.0 kg)(9.8 m/s^2)(336 m)=1.91\cdot 10^5 J

So, the mechanical energy is

E=K+U=2.85\cdot 10^5 J+1.91 \cdot 10^5 J=4.76\cdot 10^5 J

And the work done by friction is equal to the difference between the initial mechanical energy of the projectile, and the new mechanical energy:

W=E_f-E_i=4.76\cdot 10^5 J-6.43\cdot 10^5 J=-1.67 \cdot 10^5 J

And the work is negative because air friction is opposite to the direction of motion of the projectile.

(c) 88.1 m/s

The work done by air friction when the projectile goes down is one and a half times (which means 1.5 times) the work done when it is going up, so:

W=(1.5)(-1.67\cdot 10^5 J)=-2.51\cdot 10^5 J

When the projectile hits the ground, its potential energy is zero, because the heigth is zero: h=0, U=0. So, the projectile has only kinetic energy:

E = K

The final mechanical energy of the projectile will be the mechanical energy at the point of maximum height plus the work done by friction:

E_f = E_h + W=4.76\cdot 10^5 J +(-2.51\cdot 10^5 J)=2.25\cdot 10^5 J

And this is only kinetic energy:

E=K=\frac{1}{2}mv^2

So, we can solve to find the final speed:

v=\sqrt{\frac{2E}{m}}=\sqrt{\frac{2(2.25\cdot 10^5 J)}{58 kg}}=88.1 m/s

4 0
3 years ago
Other questions:
  • A truck accelerates at 5m/s2. Find the truck's mass if the driver applies a force of 425N(can you also show free diagram)?
    8·2 answers
  • A Tennis ball falls from a height 40m above the ground the ball rebounds
    13·1 answer
  • How does the motion of an airplane compare to the motion of a rocket ?
    11·1 answer
  • A mass M is attached to an ideal massless spring. When this system is set in motion with amplitude A, it has a period T. What is
    5·1 answer
  • NEED HELP QUICK!
    8·2 answers
  • Derive the expression for the range of the ball as a function of its height. To do this you should use the following steps. In t
    7·1 answer
  • A 120-V rms voltage at 60.0 Hz is applied across an inductor, a capacitor, and a resistor in series. If the rms value of the cur
    7·1 answer
  • Identical particles, each with energy E, are incident on the following four potential energy
    12·1 answer
  • discharge occurs when oppositely charged objects get close enough for the air between them to become electrically charged.
    12·1 answer
  • Tips to get friends?
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!