The chemical reaction between the reactants:
3 AgNO₃ (aq) + FeCl₃ (aq) → 3 AgCl (s) + Fe(NO₃)₃ (aq)
Explanation:
We have the following chemical reaction:
3 AgNO₃ (aq) + FeCl₃ (aq) → 3 AgCl (s) + Fe(NO₃)₃ (aq)
Complete ionic equation:
3 Ag⁺ (aq) + 3 NO₃⁻ (aq) + Fe³⁺ (aq) + 3 Cl⁻ (aq) → 3 AgCl (s) + Fe³⁺ (aq) + 3 NO₃⁻ (aq)
We remove the spectator ions and we get the net ionic equation:
Ag⁺ (aq) + Cl⁻ (aq) → AgCl (s)
where:
(aq) - aqueous
(s) - solid
Learn more about:
net ionic equation
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Answer:
24.525 g of sulfuric acid.
Explanation:
Hello,
Normality (units of eq/L) is defined as:
![N=\frac{eq_{solute}}{V_{solution}}](https://tex.z-dn.net/?f=N%3D%5Cfrac%7Beq_%7Bsolute%7D%7D%7BV_%7Bsolution%7D%7D)
Since the sulfuric acid is the solute, and we already have the volume of the solution (500 mL) but we need it in liters (0.5 L, just divide into 1000), the equivalent grams of solute are given by:
![eq_{solute}=N*V_{solution}=1\frac{eq}{L}*0.5L=0.5 eq](https://tex.z-dn.net/?f=eq_%7Bsolute%7D%3DN%2AV_%7Bsolution%7D%3D1%5Cfrac%7Beq%7D%7BL%7D%2A0.5L%3D0.5%20eq)
Now, since the sulfuric acid is diprotic (2 hydrogen atoms in its formula) 1 mole of sulfuric acid has 2 equivalent grams of sulfuric acid, so the mole-mass relationship is developed to find its required mass as follows:
![m_{H_2SO_4}=0.5eqH_2SO_4(\frac{1molH_2SO_4}{2 eqH_2SO_4}) (\frac{98.1 g H_2SO_4}{1 mol H_2SO_4} )\\m_{H_2SO_4}=24.525 g H_2SO_4](https://tex.z-dn.net/?f=m_%7BH_2SO_4%7D%3D0.5eqH_2SO_4%28%5Cfrac%7B1molH_2SO_4%7D%7B2%20eqH_2SO_4%7D%29%20%28%5Cfrac%7B98.1%20g%20H_2SO_4%7D%7B1%20mol%20H_2SO_4%7D%20%29%5C%5Cm_%7BH_2SO_4%7D%3D24.525%20g%20H_2SO_4)
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Answer:
Equal volumes of SO2(g) and O2(g) at STP contain the same number of molecules
Explanation:
According to Avogadro Law,
Equal volume of all the gases at same temperature and pressure have equal number of molecules.
This law state that volume and number of moles of gas have direct relation.
When the amount of gas increases its volume will increase and when the amount of gas decreases its volume will decrease.
Mathematical relation:
V ∝ n
V/n = K
K is proportionality constant.
When number of moles change from n₁ to n₂ and volume from V₁ to V₂
expression will be,
V₁/n₁ = K , V₂/n₂ = K
V₁/n₁ = V₂/n₂