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3 years ago

How do the Van de Graaff generator make the tape bend?

1 answer:

7 0

My Van de Graaff generator will create sparks about 10 to 12 inches in length. I like to charge myself on it and point at the aluminum blinds on the window. The charge (electronic wind) will cause the blinds to move. I can do this from about 8 feet away with ease. Soap bubbles are also interesting to play with around the Van de Graaff generator. They initially are attracted to the Van de Graaff generator and float toward it; once they become charged by the Van de Graaff generator, they float away due to repulsion. There are multitudes of fun things you can do with your Van de Graaff generator. Use your imagination!

You might be interested in

The angular width of localizers varies between ______ and ______ degrees in order to provide a signal width of approximately 700

natali 33 [55]

Answer: 10 and 35 degrees

Explanation: Localizers width below 10 degree and 35 degree signal arc is unreliable and considered unusable for navigation and as a result, aircrafts may loose alignment

5 0

4 years ago

What is the acceleration experiance by a car that takes 10s to reach 27m/s from rest

lina2011 [118]

Magnitude of acceleration = (change in speed) / (time for the change).

Change in speed = (27 - 0) = 27 m/s
Time for the change = 10 s

Magnitude of acceleration = (27 m/s) / (10 s) = 2.7 m/s² .

4 0

3 years ago

Consider a heat pump that operates on the reversed Carnot cycle with R-134a as the working fluid executed under the saturation d

Schach [20]

Answer:

Work out = 28.27 kJ/kg

Explanation:

For R-134a, from the saturated tables at 800 kPa, we get

$h_{fg}$ = 171.82 kJ/kg

Therefore, at saturation pressure 140 kPa, saturation temperature is

$T_{L}$ = -18.77°C = 254.23 K

At saturation pressure 800 kPa, the saturation temperature is

$T_{H}$ = 31.31°C = 304.31 K

Now heat rejected will be same as enthalpy during vaporization since heat is rejected from saturated vapour state to saturated liquid state.

Thus, $q_{reject}$ = $h_{fg}$ = 171.82 kJ/kg

We know COP of heat pump

COP = $\frac{T_{H}}{T_{H}-T_{L}}$

= $\frac{304.31}{304.31-254.23}$

= 6.076

Therefore, Work out put, W = $\frac{q_{reject}}{COP}$

= 171.82 / 6.076

= 28.27 kJ/kg

8 0

4 years ago

You pull a block of mass m across across a frictionless table with a constant force. you also pull with an equal constant force

KiRa [710]

For any mass m:

a = F/m
v = √2*F/m*s = √2F/sm = k/√m
Momentum = mv = k√m
Energy = 1/ mv² = 1/2 m.k²/m = 1/2k²

SO
Both will have same energy
The larger mass will have greater momentum

4 0

4 years ago

How much kinetic energy does a moving 100 kg object have if it is moving at 5 m/s?

Vesnalui [34]

Answer:

The object has 1250 Joules of Kinetic Energy.

Explanation:

Kinetic Energy = $\frac{1}{2}$ mass*velocity²

KE = $\frac{1}{2}$ mv²

KE = $\frac{1}{2}$ (100kg)(5m/s)²

KE = $\frac{1}{2}$ (100kg)(25m/s²)

KE = 1250 $\frac{kg}{m/s^2}$

KE = 1250J

4 0

4 years ago