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2 years ago

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Adoption process of the SI system by all the worlds nations is called

1 answer:

Licemer1 [7]2 years ago

6 0

Adoption process of the SI system by all the worlds nations is called Metrication or metrification.

Metrication or metrification is defined as conversion to the metric system of units of measurement. Earlier, many traditional and local systems were used for conversion but since last 2 centuries, most of the countries have adopted the SI system that is widely used as system of measurement.

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Light of wavelength 436.1 nm falls on two slits spaced 0.31 mm apart. What is the required distance from the slits to the screen

kakasveta [241]

Answer:

The correct answer is "4.26 m".

Explanation:

Given:

Wavelength,

$\lambda = 436.1 \ nm$

or,

$=436.1\times 10^{-9} \ m$

Distance,

$d = 0.31 \ mm$

or,

$=0.31\times 10^{-3} \ m$

Distance between the 1st and 2nd dark fringes,

$(y_2-y_1) = 6\times 10^{-3} \ m$

As we know,

⇒ $\frac{d}{L} (y_2-y_1) = \lambda$

or,

⇒ $L=\frac{d(y_2-y_1)}{\lambda}$

By substituting the values, we get

$=\frac{0.31\times 6\times 10^{-6}}{436.1\times 10^{-9}}$

$=\frac{0.31\times 6\times 10^3}{436.1}$

$=\frac{1860}{436.1}$

$=4.26 \ m$

3 0

2 years ago

Science is the process of asking scientific questions about which of the following?

Eva8 [605]

the answer to your question would be D.

4 0

3 years ago

Read 2 more answers

A 2.2 m long simple pendulum oscillates with a period of 4.8 s on the surface of unknown planet. What is the surface gravity of

Vsevolod [243]

Answer:

$g=3.76\ m/s^2$

Explanation:

Given that,

The length of a simple pendulum, l = 2.2 m

The time period of oscillations, T = 4.8 s

We need to find the surface gravity of the planet. The time period of the planet is given by the relation as follows :

$T=2\pi \sqrt{\dfrac{l}{g}} \\\\T^2=4\pi ^2\times \dfrac{l}{g}\\\\g=\dfrac{4\pi ^2 l}{T^2}$

Put all the values,

$g=\dfrac{4\pi ^2 \times 2.2}{(4.8)^2}\\\\=3.76\ m/s^2$

So, the value of the surface gravity of the planet is equal to $3.76\ m/s^2$ .

7 0

3 years ago

Charge Q = +4.00 mC is distributed uniformly over the volume of an insulating sphere that has radius R = 5.00 cm. What is the po

sattari [20]

Answer:

3.6 x 10^8 V

Explanation:

Q = 4 m C = 4 x 10^-3 C

r = 5 cm = 0.05 m

The formula for the potential at the surface is

Vs = K Q / r = (9 x 10^9 x 4 x 10^-3) / 0.05 = 7.2 x 10^8 V

The formula for the potential at the centre is

Vc = 3/2 Vs

Vc = 1.5 x 7.2 x 10^8 V = 10.8 x 10^8 V

The difference in potential is

V = Vc - Vs = 10.8 x 10^8 - 7.2 x 10^8 = 3.6 x 10^8 V

8 0

3 years ago

How many hydrogen atoms are present in one molecule of an ammonium acetate NH4C2H3O2?

koban [17]

Answer:

7 Molecules

Explanation:

H4 and H3 are hydrogens, just add then and you've counted the number of Hydrogens

5 0

2 years ago