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sweet [91]
3 years ago
6

How many grams are in 4.81 x 10^24 atoms of Li?

Chemistry
1 answer:
stellarik [79]3 years ago
3 0
We are given with a compound, Lithium (Li) having a 4.8x 10 ^24 atoms. We are tasked to solve for it's corresponding grams.Note that 1 mol=6.022x10^{23} atoms and Li has 6.94 g/mol, hence,g Li= 4.8x 10 ^24 atoms x 1 mol/6.022x10^{23} atoms x  6.94 g Li/1mol Li= 
55.32 g

 Therefore, the grams of Lithium is 55.32 g.

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3 years ago
As the tempreture of a liquid increases the solubility of a liquid of that liquid
anzhelika [568]
As the temperature increases, the solubility of the solute in the liquid also increases.  This is due to the fact that the increase in energy allows the liquid to more effectively break up the solute.  The additoin of energy also shifts the equilibrium of the reation to the right since it takes energy to dissolve most things and you are adding more of it (this is explained with Le Chatlier principles).

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3 years ago
Which one is the least reactive element is<br> Ar<br> Na<br> СІ<br> Mg
34kurt

Answer:

Ar

Explanation:

does not react with anything it has a full electron shell so it does not combine and it is a noble gas

7 0
2 years ago
Suppose the half-life is 9.0 s for a first order reaction and the reactant concentration is 0.0741 M 50.7 s after the reaction s
bazaltina [42]

<u>Answer:</u> The time taken by the reaction is 84.5 seconds

<u>Explanation:</u>

The equation used to calculate half life for first order kinetics:

k=\frac{0.693}{t_{1/2}}

where,

t_{1/2} = half-life of the reaction = 9.0 s

k = rate constant = ?

Putting values in above equation, we get:

k=\frac{0.693}{9}=0.077s^{-1}

Rate law expression for first order kinetics is given by the equation:

k=\frac{2.303}{t}\log\frac{[A_o]}{[A]}     ......(1)

where,

k = rate constant  = 0.077s^{-1}

t = time taken for decay process = 50.7 sec

[A_o] = initial amount of the reactant = ?

[A] = amount left after decay process =  0.0741 M

Putting values in equation 1, we get:

0.077=\frac{2.303}{50.7}\log\frac{[A_o]}{0.0741}

[A_o]=3.67M

Now, calculating the time taken by using equation 1:

[A]=0.0055M

k=0.077s^{-1}

[A_o]=3.67M

Putting values in equation 1, we get:

0.077=\frac{2.303}{t}\log\frac{3.67}{0.0055}\\\\t=84.5s

Hence, the time taken by the reaction is 84.5 seconds

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