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marshall27 [118]
3 years ago
6

A satellite is orbiting Earth in an approximately circular path. It completes one revolution each day (86,400 seconds). Its orbi

tal distance is 22,500 kilometers from the Earth's center. What is the satellite's average speed?
Physics
1 answer:
stira [4]3 years ago
6 0
@AL2006 had answered this before: Well, first of all, wherever you got this question from has done 
a really poor job of question-writing.  There are a few assorted 
blunders in the question, both major and minor ones:

-- 22,500 is the altitude of a geosynchronous orbit in miles, not km.

-- That figure of 22,500 miles is its altitude above the surface, 
   not its radius from the center of the Earth. 

-- The orbital period of a synchronous satellite has to match 
    the period of the Earth's rotation, and that's NOT 24 hours.  
    It's about 3 minutes 56 seconds less ... about 86,164 seconds. 

Here's my solution to the question, using some of the wreckage 
as it's given, and correcting some of it.  If you turn in these answers
as homework, they'll be marked wrong, and you'll need to explain 
where they came from.  If that happens, well, serves ya right for
turning in somebody else's answers for homework.


The satellite is traveling a circle. The circle's radius is 26,200 miles
(not kilometers) from the center of the Earth, so its circumference 
is (2 pi) x (26,200 miles) = about 164,619 miles.

    Average speed = (distance covered) / (time to cover the distance)

                             = (164,619 miles) / day
                                (264,929 km)

                             =      6,859 miles per hour
                                  (11,039 km) 

                           =          1.91 miles per second
                                      (3.07 km)
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It holds more weight in the regular water.
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3 years ago
The concentration of a solution that contains 70g of H2SO4 in 0,28 dm³ of solution is?​
Simora [160]

Taking into account the definition of molarity, the concentration of a solution that contains 70 g of H₂SO₄ in 0,28 dm³ of solution is 2.5510 \frac{moles}{L}.

<h3>Definition of molarity</h3>

Molar concentration or molarity is a measure of the concentration of a solute in a solution and indicates the number of moles of solute that are dissolved in a given volume.

The molarity of a solution is calculated by dividing the moles of solute by the volume of the solution:

Molarity=\frac{number of moles}{volume}

Molarity is expressed in units \frac{moles}{L}.

<h3>This case</h3>

In this case, you have:

  • number of moles= 70 g×\frac{1 mole}{98 g}= 0.7143 moles, where 98 g/mole os the molar mass of H₂SO₄
  • volume= 0.28 dm³= 0.28 L (being 1 dm³= 1 L)

Replacing in the definition of molarity:

Molarity=\frac{0.7143 moles}{0.28 L}

Solving:

<u><em>Molarity= 2.5510 </em></u>\frac{moles}{L}

Finally, the concentration of a solution that contains 70 g of H₂SO₄ in 0,28 dm³ of solution is 2.5510 \frac{moles}{L}.

Learn more about molarity:

brainly.com/question/9324116

brainly.com/question/10608366

brainly.com/question/7429224

#SPJ1

4 0
1 year ago
The vectors of a balance force are drawn...
soldi70 [24.7K]
A) same magnitude in opposite directions
5 0
3 years ago
A student wishes to determine the heat capacity of a coffee-cup calorimeter. After she mixes 94.8 g of water at 60.4°C with 94.8
madreJ [45]

Answer:

396.65 JC⁻¹

Explanation:

m_{a} = mass of water added to calorimeter = 94.8 g

T_{ai} = initial temperature of the water added = 60.4 C

c_{w} = specific heat of water = 4.184 Jg⁻¹C⁻¹

m_{c} = mass of water available to calorimeter = 94.8 g

T_{ci} = initial temperature of the water in calorimeter = 22.3 C

T_{f} = final equilibrium temperature = 35 C

Q_{C} = Heat gained by calorimeter

Using conservation of heat

Heat gained by calorimeter = Heat lost by water added - heat gained by water in calorimeter

Q_{C} = m_{a} c_{w} (T_{ai} - T_{f}) -  m_{c} c_{w} (T_{f} - T_{ci})

Q_{C} = (94.8) (4.184) (60.4 - 35) -  (94.8) (4.184) (35 - 22.3)

Q_{C} = 5037.4 J

T = Change in temperature of calorimeter

Change in temperature of calorimeter is given as

T = T_{f} - T_{ci}

T = 35 - 22.3

T = 12.7 C

Heat capacity of calorimeter is given as

c_{cm} = \frac{Q_{C}}{T}

c_{cm} = \frac{5037.4}{12.7}

c_{cm} = 396.65 JC⁻¹

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3 years ago
You have a large flashlight that takes 4 D-cell batteries, each with a voltage of 1.5 volts. If the current in the flashlight is
Naddik [55]
Ohm's law states that,
                                  V = I x R
where V, I, and R are voltage, current, and resistance, respectively. Rearranging the equation gives,
                                      R = V / I
Replacing the variables with the given values,
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The answer is letter B. 0.75 ohms. 
3 0
3 years ago
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