Question

Consider the reaction H2SO4 + 2 NaOH -> Na2SO4 + 2H2O as it represents an acid-base tritration. The equivalence point occurs when 25.34 mL of 0.2767 M NaOH is added to a 39.54 mL portion of H2SO4. What is the molar concentration of H2SO4 expressed in M?

Answer 1

We consider the given reaction H2SO4 + 2 NaOH -> Na2SO4 + 2H2O as applies to an acid-base titration.
            moles NaOH = c · V = 0.2767 mmol/mL · 25.34 mL = 7.011578 mmol
            moles H2SO4 = 7.011578 mmol NaOH · 1 mmol H2SO4 / 2 mmol NaOH
                                      = 3.505789 mmol
Hence
            [H2SO4]= n/V = 3.505789 mmol / 39.54 mL = 0.08866 M
The answer to this question is  [H2SO4] = 0.08866 M