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3 years ago

Please help on this one ? :)

Physics

2 answers:

Mamont248 [21]3 years ago

5 0

KE depends on velocity. It is easier to answer this question in terms of the earth.

The closer the object (earth/comet) is to the sun, the faster it moves. that means that the fastest moving point would be as the comet/earth passes through point C.

The slowest speed would be the furthest away from the sun which is point A.

Answer: The faster the planet moves the greater the Kinetic Energy.

The Slower the planet moves, the less the KE.

Point A is where it is slowest with the lowest amount of energy.

Discussion

The formula for KE is KE = 1/2mv^2. The mass of the comet or earth is a constant. It doesn't change no matter which point the comet passes through. If v goes down KE will go down. If v goes up, KE goes up.

skelet666 [1.2K]3 years ago

5 0

You posted the same picture yesterday, and learned that ‘C’ is the point of the MOST kinetic energy because it’s closest to the sun and moving fastest. Then I suggested that you review Kepler’s 2nd law.

From that answer OR from Kepler, it should be clear that the LEAST kinetic energy is at ‘A’ .

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Match the major muscle group with its functional role.

Naily [24]

Answer:

Abdominal

Sitting up, postural alignment

Biceps

Lifting, pulling

Deltoids

Overhead lifting

Erector Spinae

Postural alignment

Gastronemius & Soleus

Push off for walking, standing on tiptoes

Gluteus

Climbing stairs, walking, standing up

Hamstrings

Walking

Latissimus Dorsi & Rhomboids

Postural alignment, pulling open a door

Obliques

Rotation and side flexion of body

Pectoralis

Push up, pull up, bench press

Quadriceps

Climbing stairs, walking, standing up

Trapezius

Moves head sideways

Triceps

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God bless you. Because my soul almost left my body when i had to do this.

7 0

3 years ago

1 point

s2008m [1.1K]

Answer:

The person has no displacement

Explanation:

The given parameters are

The location of the person = The equator

The distance covered in one revolution = Total distance around the body

The total distance around the Earth = The circumference of the Earth = 40.075 kilometres

The total distance moved by the person standing at the equator during the Earths complete revolution = 40,075 kilometres

The initial location of the person in relation to a fixed point in space outside Earth at the start of the revolution = x km

The final location of the person in relation to the fixed point in space outside Earth at the completion of the revolution = x km

The displacement = Change in position = Final location - Initial location

∴ The displacement = x km - x km = 0 km.

5 0

4 years ago

For Part A, Sebastian decided to use the copper cylinder. How would the magnitude of his q and ∆H compare if he were to redo Par

Vitek1552 [10]

The magnitudes of his q and ∆H for the copper trial would be lower than the aluminum trial.

The given parameters;

initial temperature of metals, = $T_m$
initial temperature of water, = $T_i$
specific heat capacity of copper, $C_p$ = 0.385 J/g.K
specific heat capacity of aluminum, $C_A$ = 0.9 J/g.K
both metals have equal mass = m

The quantity of heat transferred by each metal is calculated as follows;

Q = mcΔt

For copper metal, the quantity of heat transferred is calculated as;

$Q_p = (m_wc_w + m_pc_p)(T_m - T_i)\\\\Q_p = (T_m - T_i)(m_wc_w ) + (T_m - T_i)(m_pc_p)\\\\Q_p = (T_m - T_i)(m_wc_w ) + 0.385m_p(T_m - T_i)\\\\m_p = m\\\\Q_p = (T_m - T_i)(m_wc_w ) + 0.385m(T_m - T_i)\\\\let \ (T_m - T_i)(m_wc_w ) = Q_i, \ \ \ and \ let \ (T_m- T_i) = \Delta t\\\\Q_p = Q_i + 0.385m\Delta t$

The change in heat energy for copper metal;

$\Delta H = Q_p - Q_i\\\\\Delta H = (Q_i + 0.385m \Delta t) - Q_i\\\\\Delta H = 0.385 m \Delta t$

For aluminum metal, the quantity of heat transferred is calculated as;

$Q_A = (m_wc_w + m_Ac_A)(T_m - T_i)\\\\Q_A = (T_m -T_i)(m_wc_w) + (T_m -T_i) (m_Ac_A)\\\\let \ (T_m -T_i)(m_wc_w) = Q_i, \ and \ let (T_m - T_i) = \Delta t\\\\Q_A = Q_i \ + \ m_Ac_A\Delta t\\\\m_A = m\\\\Q_A = Q_i \ + \ 0.9m\Delta t$