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dimulka [17.4K]
2 years ago
8

What is the balanced, net ionic equation

Chemistry
1 answer:
Effectus [21]2 years ago
3 0

A net ionic equation which tends to show the ions that underwent a change in the reaction

<h3>What is a reaction equation?</h3>

The term reaction equation is the term that can be used to describe the instance where reactants combine together. If this occurs in solution we can say that the reaction is an aqueous phase reaction because the reactants wee all dissolved in solution.

It is possible for ionic substances in solution to react. When this occurs, it is possible for us to put down a net ionic equation which tends to show the ions that underwent a change in the reaction and the product of this reaction may be a liquid, a gas or a solid.

In this case, the complete molecular equation can be written as;

Ba(NO3)2(aq) + Na2SO4(aq) -----> BaSO4(s) + 2NaNO3(aq)

The complete ionic equation can be written as;

Ba^2+(aq) + 2NO3^-(aq) + 2Na^+(aq) + SO4^2-aq)  -----> BaSO4(s) +  2NO3^-(aq) + 2Na^+(aq)

Net ionic equation is;

Ba^2+(aq) + + SO4^2-aq)  -----> BaSO4(s)

Learn more about balanced reaction equation:brainly.com/question/22064431

#SPJ1

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Answer:

"Well, by definition,

molarity=

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Explanation:

THE LINES UNDER <u>moles of solute </u>MEANS ITS OVER volume of solution"

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Considering the following precipitation reaction: Pb(NO3)2(aq) + 2KI(aq) → PbI2(s) + 2KNO3(aq) Which ion would NOT be present in
Allisa [31]

Answer:

The question is incomplete and confusing.

  • In the complete ionic equation you write all the ions that are formed. Those are: Pb²⁺, NO₃⁻, K⁺, and I⁻. They all are present in the complete ionic equation.

  • In the net ionic equation, the spectator ions do not appear. They are: NO₃⁻ and K⁺. They would not be present in the net ionic equation, but they do in the complete ionic equation.

See below the details.

Explanation:

Which compound will not form ions?

<u />

<u>1. Write the balanced molecular equation:</u>

  • Pb(NO₃)₂(aq) + 2KI(aq) → PbI₂(s) + 2KNO₃(aq)

<u />

<u>2. Write the ionizations for the ionic aqueous compounds:</u>

<u />

  • Pb(NO₃)₂(aq) →  Pb⁺²(aq) + 2NO₃⁻(aq)

  • 2KI(aq) → 2K⁺(aq) + 2I⁻(aq)

  • 2KNO₃(aq) → 2K⁺(aq) + 2NO₃⁻(aq)

<u />

<u>3. Write the complete ionic equation:</u>

Pb⁺²(aq) + 2NO₃⁻(aq) + 2K⁺(aq) + 2I⁻(aq) → PbI₂(s) +  2K⁺(aq) + 2NO₃⁻(aq)

Hence, since PbI₂(s) does not ionize, but stays in solid form, it will not form ions.

All, Pb⁺², NO₃⁻, K⁺, and I⁻ will be present in the total ionic equation.

It is in the net ionic equation that the spectator ions are removed. Those, are NO₃⁻ and K⁺, because they are on both sides of the complete ionic equation.

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3 years ago
1. How much heat is required to melt 25.0 g of ice at 0°C?
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Answer: The heat required to melt 25.0 g of ice at 0^0C is 8350 Joules

Explanation:

Heat of Fusion tells us how much energy is needed to convert 1g of a solid to a liquid at the same temperature.

Q=m\times L

Q = Heat absorbed = ?  

m = mass of ice = 25.0 g

L = Latent heat of fusion of ice = 334 J/g

Putting in the values, we get:

Q=25.0g\times 334J/g=8350J

Thus heat required to melt 25.0 g of ice at 0^0C is 8350 Joules

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