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3 years ago

How does kinetic energy affect the stopping distance of a small vehicle compared to a large vehicle?

1 answer:

Studentka2010 [4]3 years ago

8 0

Kinetic energy is the energy applied or present in a moving object. According to Newton's second law of motion the magnitude of acceleration of an object is proportional to the magnitude of the net force but inversely proportional to its mass. So the Kinetic Energy of a moving car of small vehicle is greater than the large vehicle if both are applied with the same net force. The greater the Kinetic Energy the longer the stopping distance

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A flywheel with a diameter of 1.63 m is rotating at an angular speed of 79.9 rev/min. (a) What is the angular speed of the flywh

Studentka2010 [4]

Answer:

(a) 8.362 rad/sec

(b) 6.815 m/sec

(d) 396.22 revolution

Explanation:

We have given that diameter d = 1.63 m

So radius $r=\frac{d}{2}=\frac{1.63}{2}=0.815m$

Angular speed N = 79.9 rev/min

(a) We know that angular speed in radian per sec

$\omega =\frac{2\pi N}{60}=\frac{2\times 3.14\times 79.9}{60}=8.362rad/sec$

(b) We know that linear speed is given by

$v=r\omega =0.815\times 8.362=6.815m/sec$

And $\omega _i=79.9rev/min$

Time t = 63 sec

Angular acceleration is given by $\alpha =\frac{\omega _f-\omega _i}{t}=\frac{675-79.9}{63}=9.446rad/sec^2$

(d) Change in angle is given by

$\Theta =\frac{1}{2}(\omega _i+\omega _f)t=\frac{1}{2}(675+79.9)\times 1.05=396.22rev$

7 0

3 years ago

If the timber weighs 670 N, calculate its angle of inclination when the water surface is 2.1 m above the pivot. Above what depth

Ymorist [56]

Answer:

Q = 40.1 degrees

Explanation:

Given:

- The weight of the timber W = 670 N

- Water surface level from pivot y = 2.1 m

- The specific density of water Y = 9810 N / m^3

- Dimension of timber = (0.15 x 0.15 x 0.0036) m

Find:

- The angle of inclination Q that the timber makes with the horizontal.

Solution:

- Calculate the Flamboyant Force F_b acting upwards at a distance x along the timber, which is unknown:

F_b = Y * V_timber

F_b = 9810*0.15*0.15*x

F_b = 226.7*x N

- Take static equilibrium conditions for the timber, and take moments about the pivot:

(M)_p = 0

W*0.5*3.6*cos(Q) - x/2 * F_b*cos(Q) = 0

- Plug values in:

670*0.5*3.6 - x^2 * 0.5*226.7 = 0

x^2 = 1206 / 113.35

x = 3.26 m

- Now use the value of x and vertical height y to compute the angle of inclination to be:

sin(Q) = y / x

sin(Q) = 2.1 / 3.26

Q = sin^-1 (0.6441718)

Q = 40.1 degrees

5 0

3 years ago

Assapp!!!’!!!!!!!! !!!!!!

dlinn [17]

Answer:

delta r(x) = (delta (r)) * cos(alpha), delta r(y) = (delta(r)) * sin(alpha)

Explanation:

Well it's a simple rule I guess...

6 0

3 years ago

A wave is traveling at 241 m/s. It has a wavelength of 30.0 m. What is its frequency?

Feliz [49]

Answer:

A) 8.03Hz

Explanation:

f = V/λ

Where wavelength( λ )= 30m

Speed (V) =241m/S

f= 241/30=8.03Hz

3 0

4 years ago

slader the cross section of a 5-ft long trough is an isosceles trapezoid with a 2 foot lower base, a 3-foot upper base, and an a

Ostrovityanka [42]

Answer:

0.08 ft/min

Explanation:

To get the speed at witch the water raising at a given point we need to know the area it needs to fill at that point in the trough (the longitudinal section), which is given by the height at that point.

So we need to get the lenght of the sides for a height of 1 foot. Given the geometry of the trough, one side is the depth d and the other (lets call it l) is given by:

$l=\frac{3-2}{2}\,ft+2\,ft\\l=2.5\,ft$

since the difference between the upper and lower base is the increase in the base and we are only at halft the height.

Now we can calculate the longitudinal section A at that point:

$A=d\times l\\A=5\,ft \times 2.5\, ft\\A=12.5\, ft^{2}$

And the raising speed v of the water is given by:

$v=\frac{q}{A}\\v=\frac{1\, \frac{ft^3}{min}}{12.5\, ft^2}\\v=0.08\, \frac{ft}{min}$

where q is the water flow (1 cubic foot per minute).

7 0

4 years ago