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Mandarinka [93]
3 years ago
5

What is the energy of a photon whose frequency is 5.0x10^14 hz

Physics
1 answer:
igomit [66]3 years ago
5 0

Answer:

Energy of a photon is 3.313\times 10^{-19}\textrm{ J}

Explanation:

Given:

Frequency of the photon is, f=5.0\times 10^{14}\textrm{ Hz}.

Energy of a photon of frequency f is given as:

E=hf, where, h is called Planck's constant.

h = 6.626\times 10^{-34}\textrm{ J.s}

So, energy of a photon is:

E= 6.626\times 10^{-34}\times 5.0\times 10^{14}=3.313\times 10^{-19}\textrm{ J}

Therefore, the energy of a photon whose frequency is 5.0\times 10^{14} Hz is 3.313\times 10^{-19}\textrm{ J}.

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Assume that at sea-level the air pressure is 1.0 atm and the air density is 1.3 kg/m3.
scoundrel [369]

Answer

Pressure, P = 1 atm

air density, ρ = 1.3 kg/m³

a) height of the atmosphere when the density is constant

   Pressure at sea level = 1 atm = 101300 Pa

   we know

   P = ρ g h

   h = \dfrac{P}{\rho\ g}

   h = \dfrac{101300}{1.3\times 9.8}

          h = 7951.33 m

height of the atmosphere will be equal to 7951.33 m

b) when air density decreased linearly to zero.

  at x = 0  air density = 0

  at x= h   ρ_l = ρ_sl

 assuming density is zero at x - distance

 \rho_x = \dfrac{\rho_{sl}}{h}\times x

now, Pressure at depth x

dP = \rho_x g dx

dP = \dfrac{\rho_{sl}}{h}\times x g dx

integrating both side

P = g\dfrac{\rho_{sl}}{h}\times \int_0^h x dx

P =\dfrac{\rho_{sl}\times g h}{2}

 now,

h=\dfrac{2P}{\rho_{sl}\times g}

h=\dfrac{2\times 101300}{1.3\times 9.8}

  h = 15902.67 m

height of the atmosphere is equal to 15902.67 m.

6 0
3 years ago
A caterpillar crawls 20 feet in 5 minutes. What is the caterpillars crawling speed?
Pavel [41]
The equation is
s= d/t

In this case you would have to write it out as:
s= 20/5
Speed = 4
6 0
3 years ago
Which law explains how light changes as temperature increases?
gayaneshka [121]
Wein’s Law, search it up if you need more info
7 0
3 years ago
A 1200 kg car accelerates from 13 m/s to 17 m/s. find the change in momentum of the car.
mixas84 [53]
P=4800kgm/s
As
p=mΔv
where p is momentum, m is mass and v is velocity
Given values is
m =1200kg
Δv= 17m/s-13m/s=4m/s
Now
p=mΔv
p=(1200kg)*(4m/s)
p=4800kgm/s


8 0
2 years ago
5.
lesantik [10]

Answer:

It is B

it is called a jumper cable because it jumps the power from one car to the other

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3 years ago
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