Question

(will give brainliest to whoever is first and gives reason) A mass is spun in a circle with a frequency of 40Hz. What is the period of its rotation?

Answer 1

Answer:

$\huge\boxed{T = 0.025\ seconds}$

Explanation:

Given:

Frequency = f = 40 Hz

Required:

Time period = T = ?

Formula:

$\sf T = 1 / f$

Solution:

T = 1 / 40

T = 0.025 seconds

$\rule[225]{225}{2}$

Hope this helped!

~AH1807