All categories

3 years ago

A ball rolls from x=-5 to x=32.4 m in 8.9 seconds. What was it’s average velocity

Physics

2 answers:

fenix001 [56]3 years ago

5 0

Answer:

4.157 m/s

Explanation:

Average velocity: This can be defined as the ratio change in position to time interval. The S.I unit of average velocity is m/s

The expression for average velocity is given as,

V = Δx/t.............. Equation 1

Where V = average velocity, Δx = change in position on the x- axis, t = time.

But,

Δx = x₂-x₁........... Equation 2

Substitute equation 2 into equation 1

V = (x₂-x₁)/t................ Equation 3

Given: x₂ = 32.4 m, x₁ = -5 m, t = 8.9 s

Substitute into equation 3

V = [32.4-(-5)]/8.9

V = (32.4+5)/8.9

V = 37.4/8.9

V = 4.157 m/s

Hence the average velocity = 4.157 m/s

puteri [66]3 years ago

5 0

Answer:

v = 4.20m/s

Average velocity is 4.20m/s

Explanation:

Average velocity is the change in displacement per unit time;

v = ∆x/t

Given;

∆x = 32.4 - (-5) = 37.4 m

t = 8.9 seconds

Substituting the values;

v = 37.4m/8.9s

v = 4.20m/s

Average velocity is 4.20m/s

You might be interested in

A large fraction of the ultraviolet (UV) radiation coming from the sun is absorbed by the atmosphere. The main UV absorber in ou

irakobra [83]

Answer:

λ = 3.2 x 10⁻⁷ m = 320 nm

Explanation:

The relationship between the velocity of electromagnetic waves (UV rays) and the their frequency is:

v = fλ

where,

v = c = speed of the electromagnetic waves (UV rays) = speed of light

c = 3 x 10⁸ m/s

f = frequency of the electromagnetic waves (UV rays) = 9.38 x 10¹⁴ Hz

λ = wavelength of the electromagnetic waves (UV rays) = ?

Therefore, substituting the values in the relation, we get:

3 x 10⁸ m/s = (9.38 x 10¹⁴ Hz)(λ)

λ = (3 x 10⁸ m/s)/(9.38 x 10¹⁴ Hz)

λ = 3.2 x 10⁻⁷ m = 320 nm

So, the radiation of 320 nm wavelength is absorbed by Ozone.

3 0

3 years ago

Read 2 more answers

un resorte de 10cm de longitud recibe una magnitud de fuerza que lo estira hasta medir 15cm ¿cual es la magnitud de la tension u

Ber [7]

Answer: 0.5

Explanation:

The modulus of elasticity (called "alargamiento unitario" in spanish) $\epsilon$ of a spring is given by the following formula:

$\epsilon=\frac{\Delta L}{L}$

Where:

$L=10 cm$ is the original length of the spring

$\Delta L=L_{f}-L$ is the elongation of the spring, being $L_{f}=15 cm$ the length of the spring after a force is applied to it.

$\epsilon=\frac{L_{f}-L}{L}=\frac{15 cm - 10 cm}{10 cm}$

Then:

$\epsilon=0.5$

8 0

3 years ago

A 200 g load attached to a horizontal spring moves in simple harmonic motion with a period of 0.410 s. The total mechanical ener

defon

Complete question:

A 200 g load attached to a horizontal spring moves in simple harmonic motion with a period of 0.410 s. The total mechanical energy of the spring–load system is 2.00 J. Find

(a) the force constant of the spring and (b) the amplitude of the motion.

Answer:

(a) the force constant of the spring = 47 N/m

(b) the amplitude of the motion = 0.292 m

Explanation:

Given;

mass of the spring, m = 200g = 0.2 kg

period of oscillation, T = 0.410 s

total mechanical energy of the spring, E = 2 J

The angular speed is calculated as follows;

$\omega = \frac{2\pi}{T} \\\\\omega = \frac{2\pi}{0.41} \\\\\omega = 15.33 \ rad/s$

(a) the force constant of the spring

$\omega = \sqrt{\frac{k}{m} } \\\\\omega^2 = \frac{k}{m} \\\\k = m \omega^2\\\\k = (0.2)(15.33)^2\\\\k = 47 \ N/m$

(b) the amplitude of the motion

E = ¹/₂kA²

2E = kA²

A² = 2E/k

$A = \sqrt{\frac{2E}{k} } \\\\A = \sqrt{\frac{2\times 2}{47} }\\\\A = 0.292 \ m$

7 0

2 years ago

A battery has an electric potential of 1.5V and transfers 10.0 C between the two terminals. How much work was done?

bogdanovich [222]

Answer:

15 Joules

Explanation:

work = charge x potential difference

= 10 x 1.5

= 15

8 0

2 years ago

What is the total force acting on the ball in the diagram? How would you describe its velocity?

KonstantinChe [14]

Answer:

Velocity formulae should be used in order to know the answer

8 0

2 years ago

Read 2 more answers