Answer:
Explanation:
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Based on the given reaction, since magnesium and water are in a 1:2 molar ratio at the reactants, we must apply the following stoichiometric factors to compute the complete reaction of the 6.0 g of magnesium:
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Solids; Ice and Sugar.
Liquids; Water and Milk.
Gases; Air and Helium.
Answer:
31.3grams
Explanation:
The amount of a radioactive element that remains, N(t), can be calculated by using the formula;
N(t) = N(o) × 0.5^{t/t(1/2)}
Where;
N(t) = mass of substance remaining
N(o) = mass of original substance
t(1/2) = half-life of substance
t = time elapsed
From the provided information; N(t) = ?, N(o) = 250g, t(1/2) = 1599 years, t = 4797 years
N(t) = 250 × 0.5^{4797/1599}
N(t) = 250 × 0.5^(3)
N(t) = 250 × 0.125
N(t) = 31.25g
N(t) = 31.3grams
Answer:
The process by which a body of water becomes enriched in dissolved nutrients (such as phosphates) that stimulate the growth of aquatic plant life usually resulting in the depletion of dissolved oxygen.