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Westkost [7]
3 years ago
11

What is the wavelength of microwaves of 3.0 × 10^9 Hz frequency? a. 0.050 m c. 0.10 m b. 0.060 m d. 0.20 m

Chemistry
1 answer:
Alex777 [14]3 years ago
7 0

Hello!

We have the following data:

f (radiation frequency) = 3.0 × 10^9 Hz

v (speed of light) = 3*10^8\:m/s

λ (wavelength) = ? (in m)

Let's find the wavelength, let's see:

f = \dfrac{v}{\lambda}

3.0*10^9 = \dfrac{3*10^8}{\lambda}

\lambda = \dfrac{3*10^8}{3*10^9}

\lambda = 1*10^{8-9}

\lambda = 1*10^{-1}

\boxed{\boxed{\lambda = 0.1\:m}}\end{array}}\qquad\checkmark

Answer:

c. 0.10 m

________________

I Hope this helps, greetings ... DexteR! =)

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while doing a lab, a student found the density of a piece of pure aluminum to be 2.85 g/cm^3. the accepted value for the density
vagabundo [1.1K]

Answer:

Percent error = 5.6%

Explanation:

Given data:

Measured value of density by students = 2.85 g/cm³

Accepted density of aluminium = 2.70 g/cm³

Percent error = ?

Solution:

Formula:

Percent error = [ Measured value - accepted value / accepted value ]× 100

Now we will put the values in formula:

Percent error = [ 2.85 g/cm³  - 2.70 g/cm³ / 2.70 g/cm³ ]× 100

Percent error = [0.15/2.70 g/cm³ ] × 100

Percent error = 0.056× 100

Percent error = 5.6%

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6 0
3 years ago
1. A 4.00 L sample of air at 35 degrees C expands to 5.50 L when heated. What is
tatuchka [14]

Answer:

150.5 °C

Explanation:

From the question given above, the following data were obtained:

Initial volume (V₁) = 4 L

Initial temperature (T₁) = 35 °C

Final volume (V₂) = 5.5 L

Final temperature (T₂) =?

Next, we shall convert 35 °C to Kelvin temperature. This can be obtained as follow:

T(K) = T(°C) + 273

Initial temperature (T₁) = 35 °C

Initial temperature (T₁) = 35 °C + 273

Initial temperature (T₁) = 308 K

Next, we shall determine the final (i.e the new) temperature of air. This can be obtained as follow:

Initial volume (V₁) = 4 L

Initial temperature (T₁) = 308 K

Final volume (V₂) = 5.5 L

Final temperature (T₂) =?

V₁ / T₁ = V₂ / T₂

4 / 308 = 5.5 / T₂

Cross multiply

4 × T₂ = 308 × 5.5

4 × T₂ = 1694

Divide both side by 4

T₂ = 1694 / 4

T₂ = 423.5 K

Finally, we shall convert 423.5 K to celsius temperature. This can be obtained as follow:

T(°C) = T(K) – 273

T₂ = 423.5 K

T₂ = 423.5 – 273

T₂ = 150.5 °C

Thus, the new temperature of the air is 150.5 °C

3 0
3 years ago
If 30.0 grams of calcium metal react with 18.0 grams of oxygen gas, your calculations show that ________ grams of CaO could be p
jek_recluse [69]

Answer:

42g if CaO can be produced from 30g and 31.5g of CaO will be produced from 18g of O

Explanation:

40g of CA =56g

30g =×

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3 years ago
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