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3 years ago

Please someone help me !!

Physics

1 answer:

sergij07 [2.7K]3 years ago

6 0

Answer:

Explanation:

because if the solvent is more than the solvent then we can't resolve it.

so our product will be suspended

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Frost wedging occurs when water seeps into a crack in a rock, freezes, and causes the crack in the rock to widen.

Ilia_Sergeevich [38]

Answer:

the answer is true.

3 0

4 years ago

Homer Agin leads the Varsity team in home runs. In a recent game, Homer hit a 34.5 m/s sinking curve ball head on, sending it of

Aneli [31]

Answer:

–77867 m/s/s.

Explanation:

From the question given above, the following data were obtained:

Initial velocity (u) = 34.5 m/s

Final velocity (v) = –23.9 m/s

Time (t) = 0.00075 s

Acceleration (a) =?

Acceleration is simply defined as the rate of change of velocity with time. Mathematically, it is expressed as:

Acceleration = (final velocity – Initial velocity) /time

a = (v – u) / t

With the above formula, we can obtain acceleration of the ball as follow:

Initial velocity (u) = 34.5 m/s

Final velocity (v) = –23.9 m/s

Time (t) = 0.00075 s

Acceleration (a) =?

a = (v – u) / t

a = (–23.9 – 34.5) / 0.00075

a = –58.4 / 0.00075

a = –77867 m/s/s

Thus, the acceleration of the ball is –77867 m/s/s.

3 0

3 years ago

wo skaters collide and embrace in an inelastic collision. Alex's mass is 90 kg and his initial velocity is 1.5 m/s i . Barbara's

Natalija [7]

Answer:

The two skaters will move with a common speed of 1.19 m/s.

Explanation:

Given that,

Mass of Alex, $m_1=90\ kg$

Initial velocity of Alex, $u_1=1.5i\ m/s$

Mass of Barbara, $m_2=57\ kg$

Initial velocity of Barbara, $u_2=2j\ m/s$

After the collision, the two skaters move together at a common velocity. Let V is the common velocity. Using the conservation of momentum as :

$m_1u_1+m_2u_2=(m_1+m_2)V\\\\90\times 1.5i+57\times 2j=(90+57)V\\\\V=\dfrac{135i+114j}{147}\\\\V=\dfrac{135i}{147}+\dfrac{114j}{147}\\\\V=(0.91i+0.77j)\ m/s$

Magnitude of final velocity:

$|V|=\sqrt{0.91^2+0.77^2} \\\\|V|=1.19\ m/s$

So, the two skaters will move with a common speed of 1.19 m/s.

3 0

4 years ago

Read 2 more answers

A 495-kg dragster accelerates from rest to a final speed of 105 m/s in 395 m, during which it encounters an average frictional f

drek231 [11]

Answer:

Explanation:

According to energy conservation which states that the workdone is equal to change in the system

Workdone = change in kinetic energy + (frictional force * distance)

Workdone = ΔK + fd

Workdone = kf-Ki + fd

Workdone = = 1/2(m(v-u)^2) + fd

Given

Mass m = 495kg

final velocity v = 105m/s

initial velocity = 0m/s

Force f= 1400N

distance d = 395m

Substitute

Workdone = 1/2(495(105-0)^2) + 1400(395)

Workdone = 2,728,687.5+553000

Workdone = 3,281,687.5 Joules

Time = 8.2secs

Power output = Workdone/Time

Power output = 3,281,687.5/8.2

Power output = 885,766.768

Power output = 8.858 * 10^5 watts

3 0

4 years ago

How does temperature change as you go from the surface toward the center of the earth?

Nastasia [14]

Because lava is in the center and lavas hot

8 0

3 years ago