Ok, so you've got to figure out a force F and you have the speed in which the boxer punches on determinate time and the mass of the sheet of paper.
So based on the formula that says that the Force is equal to the mass multiplied by the acceleration => F=ma.
You look at it and see that you only have mass which is measured on KG so there is no problem.
then you have the acceleration which is measured on meters and is defined by: a = Δv/Δt
So now you can replace the velocity and the time you have there
⇒ a 25m/s / 0.05s
you have computing that ⇒ 50m because the seconds were cancelled out.
and then you plug the meters into the force equation.
F=(0.005kg)(50)
F=0.25N
so the boxer will have a force of 0.25 Newton's.
Explanation:
first you have to find accelerarion, it is given that the initial velocity(u) is 3 m/s, distance travelled(s) be 2m finall it came to rest so final velocity be 0m/s
now using the 3rd law of motion
v^2=u^2+2as
0=9+2a2
a= -9/4m/s^2
now force=mass×accelration
=2kg×(-9/4)m/s^2
=4.5 N
4.5 newton force applied on the book!
✌️:)
The stored heat i guess..
Answer:
ε₂ =2.63 V
Explanation:
given,
M = 0.0034 H
I (t) = I₀ sin (ωt)
I (t) = 5.4 sin (143 t)
magnitude of the induced emf in the second coil
ε₂ =
ε₂ =
for maximum emf
cos (143 t) = 1
ε₂ =
ε₂ =2.63 V
The angle measured counterclockwise from the positive x-axis is θ = 50.4°
<h3>
How to get the angle correspondent to a vector?</h3>
Here we know that the vector is:
V = < -177 cm, -214 cm>
To get the correspondent angle for this vector, we can think that this is the hypotenuse of a right triangle, such that the y-component and x-component are the cathetus.
Then, to get the angle (measured counterclockwise from the positive x-axis) is given by:
Tan(θ) = (opposite cathetus)/(adjacent cathetus)
Tan(θ) = (-214cm)/(-177 cm)
Using the inverse tangent function we get:
Atan(Tan(θ)) = Atan((-214cm)/(-177 cm))
θ = 50.4°
So the angle is 50.4°
If you want to learn more about vectors, you can read:
brainly.com/question/3184914
