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djverab [1.8K]
4 years ago
8

Scientists and engineers are working to develop ways to replace corn with a different plant, such as switchgrass, in the product

ion of ethanol. This is largely because using corn to produce ethanol could cause a problem for society. Which of the following statements best describes this problem?
A. Chemical processes do not exist that can transform corn's sugars into ethanol.
B. Grass resources are scarce and could be used up if harvested to produce ethanol.
C. Harvesting corn for ethanol could come into conflict with harvesting corn for food.
D. Chemical processes do not exist that can release the chemical energy in ethanol.
Physics
1 answer:
Alja [10]4 years ago
3 0

Answer:

C

Explanation:

Using corn to produce ethanol will significantly reduce the amount of corn, available for the food industry. Note, that corn is used not only as a food for people, but also as a good source of energy for the animals due to its high productivity. As the amount of the farming soil is limited and the humanity is facing the lack of the food already, utilizing the corn to make ethanol, specially in high volumes, will have further negative impact on the starving people. In addition, note, that ethanol will be used by rich people, who already have good access to the food, so low income society will face further issues.

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If the air pressure on the station model is 500 or more, place a 9 in front of this number. If the pressure number on the station is less than 500 add a 10 in front of this number. 

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3 years ago
A toy rocket that weights 10 N blasts straight up from ground level with an initial kinetic energy of 40J. at the exact top of i
marishachu [46]

Answer:

14 m

Explanation:

Applying,

P.E = WH............ Equation 1

Where P.E = potential energy at the highest vertical height, W = weight of the toy rocket, H = Vertical height.

Note: At the highest vertical height, the kinetic energy is 0 J

Therefore,

Mechanical energy(M.E) = Potential Energy(P.E)

make H the subject of the equation

H = P.E/W......... Equation 2

From the question,

Given: W = 10 N,  P.E = 140 J

Substitute these values in equation 2

H = 140/10

H = 14 m

8 0
3 years ago
Two balls are dropped from rest and allowed to fall. If one ball is allowed to fall for 1 s and the other for 3 s compare the di
kirill115 [55]

The second ball traveled a greater distance when compared to the first ball because the second ball spent more time in motion.

The given parameters;

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  • time of fall of the second ball, t = 3 s

The distance traveled by each ball is calculated using the second equation of motion as shown below.

The distance traveled by the first ball is calculated as follows;

h = u_0t + \frac{1}{2} gt^2\\\\h = 0 + \frac{1}{2} gt^2\\\\h = \frac{1}{2} gt^2\\\\h = (0.5\times 9.8\times 1^2)\\\\h = 4.9 \ m

The distance traveled by the second ball is calculated as follows;

h = \frac{1}{2} gt^2\\\\h = (0.5\times 9.8\times 3^2)\\\\h = 44.1\ m

Thus, the second ball traveled a greater distance because it spent more time in motion.

Learn more here:brainly.com/question/5868480

3 0
2 years ago
which object has the most gravitational potential energy? A. an 8 kg book at a height of 3m B. an 5 kg book at a height of 3 m C
astra-53 [7]
I think A is the correct answer because its high is more higher compared to the others, and the mass really does not matter, to know the gravitational potential energy, we need to know how high the object is located because gravity does not show any favor to an object that has more mass or an object that doesnt
6 0
4 years ago
Read 2 more answers
In class we calculated the range of a projectile launched on flat ground. Consider instead, a projectile is launched down-slope
zysi [14]

Answer:

With an initial speed of 10m/s at an angle 30° below the horizontal, and a height of 8m, the projectile travels 7.49m horizontally before it lands.

Explanation:

Since the horizontal motion is independent from the vertical motion, we can consider them separated. The horizonal motion has a constant speed, because there is no external forces in the horizontal axis. On the other hand, the vertical motion actually is affected by the gravitational force, so the projectile will be accelerated down with a magnitude g.

If we have the initial velocity v_o and its angle \theta, we can obtain the vertical component of the velocity v_{oy} using trigonometry:

v_{oy}=v_osin\theta

Therefore, if we know the height at which the projectile was launched, we can obtain the final velocity using the formula:

v_{fy}^{2} =v_{oy}^{2}+2gy\\\\ v_{fy}=\sqrt{v_{oy}^{2}+2gy }

Next, we compute the time the projectile lasts to reach the ground using the definition of acceleration:

g=\frac{v_{fy}-v_{oy}}{\Delta t} \\\\\Delta t= \frac{v_{fy}-v_{oy}}{g}=\frac{\sqrt{v_{oy}^{2}+2gy} -v_{oy}}{g}

Finally, from the equation of horizontal motion with constant speed, we have that:

x=v_{ox}\Delta t= v_{ox}\frac{\sqrt{v_{oy}^{2}+2gy} -v_{oy}}{g}

For example, if the projectile is launched at an angle 30° below the horizontal with an initial speed of 10m/s and a height 8m, we compute:

v_{ox}=10\frac{m}{s} cos30=8.66\frac{m}{s}\\v_{oy}=10\frac{m}{s} sin30=5\frac{m}{s}\\\\x=8.66\frac{m}{s} \frac{\sqrt{(5\frac{m}{s}) ^{2}+2(9.8\frac{m}{s^{2}})8m}-5\frac{m}{s}  }{9.8\frac{m}{s^{2} } } =7.49m

In words, the projectile travels 7.49m horizontally before it lands.

8 0
4 years ago
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