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Advocard [28]
3 years ago
9

Calculate the acceleration due to gravity on the moon. the radius of the moon is about 1.74 x 106 m and its mass is 7.35 x 1022

kg.
Physics
1 answer:
emmainna [20.7K]3 years ago
4 0
Given: Radius of the Moon Rm = 1.74 x 10⁶ m

           Mass of the Moon Mm = 7.35 X 10²² Kg

           Universal Gravitational constant G = 6.67 X 10⁻¹¹ N.m²/Kg²

Required: acceleration due to gravity g = ?



Formula:  g = GMm/Re²

                 g = (6.67 x 10⁻¹¹ N.m²/Kg²)(7.35 x 10²² Kg/(1.74 x 10⁶ m)²

                 g = 4.90 x 10¹² N.m²/Kg/3.0 x 10¹² m²

                 g = 1.63 m/s²




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finlep [7]

Answer:

Option (b) is correct.

Explanation:

Elastic collision is defined as a collision where the kinetic energy of the system remains same. Both linear momentum and kinetic energy are conserved in case of an elastic collision.

Inelastic collision is defined as a collision where kinetic energy of the system is not conserved whereas the linear momentum is conserved. This loss of kinetic energy may due to the conversion to thermal energy or sound energy or may be due to the deformation of the materials colliding with each other.

As given in the problem, before the collision, total momentum of the system is 2.5~Kg~m~s^{-1} and the kinetic energy is 5~J. After the collision, the total momentum of the system is  2.5~Kg~m~s^{-1}, but the kinetic energy is reduced to 4~J. So some amount of kinetic energy is lost during the collision.

Therefor the situation describes an inelastic collision (and it could NOT be elastic).

5 0
3 years ago
A 35 kg box rests on the back of a truck. The coefficient of static friction bet?005 (part 1 of 2)A 35 kg box rests on the back
elena-14-01-66 [18.8K]

Answer with Explanation:

We are given that

Mass of box=35 kg

Coefficient of static friction between box and truck bed=0.202

Acceleration due to gravity=9.8 m/s^2

a.We have to find the force by which the box accelerates forward.

Force by which box accelerates=\mu mg=0.202\times 9.8\times 35

Force by which box accelerates=62.286 N

b.We have to find the maximum acceleration can the truck have before the box slides.

Force =friction force

ma=\mu mg

a=\mu g=9.8\times 0.202=1.9796 m/s^2

Hence, the truck can have maximum acceleration before the box slide=1.9796 m/s^2

3 0
3 years ago
A 1200 kg car accelerates from 13 m/s to 17 m/s. find the change in momentum of the car.
mixas84 [53]
P=4800kgm/s
As
p=mΔv
where p is momentum, m is mass and v is velocity
Given values is
m =1200kg
Δv= 17m/s-13m/s=4m/s
Now
p=mΔv
p=(1200kg)*(4m/s)
p=4800kgm/s


8 0
2 years ago
A person rides a bike with a constant velocity of 2 m/s. If his total displacement is 10 meters, for how long was he riding?
TEA [102]

Answer:

5s

Explanation:

i just know

3 0
3 years ago
A rolling rock with a velocity of 20 m/s has a momentum of 5000 kg m/s. What is the rock’s mass
evablogger [386]

Answer:

<h2>250 kg</h2>

Explanation:

The mass of the rock can be found by using the formula

m =  \frac{p}{v}  \\

p is the momentum

v is the velocity

From the question we have

m =  \frac{5000}{20}  =  \frac{500}{2}  = 250 \\

We have the final answer as

<h3>250 kg</h3>

Hope this helps you

8 0
3 years ago
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