Write the balanced equation for the decomposition of hydrogen peroxide to form water and oxygen.

1 answer:

7 0

Hydrogen peroxide is H2O2, while water is H2O and oxygen (a diatomic gas) is O2. The (unbalanced) reaction is:
H2O2 --> H2O + O2
Notice that the H2O2 has 2 H atoms, and so does H2. This means that both must have the same coefficients, and we can adjust the coefficient of O2. Since H2O2 has 2 O atoms, and H2O has 1, we multiply O2 by 1/2:
H2O2 --> H2O + (1/2)O2
This has an equivalent number of H and O atoms on either side, but we want the coefficients to be whole numbers, so we multiply everything by 2:
2H2O2 --> 2H2O + O2

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A student analyzed an unknown sample that contained a single anion. The sample gave a yellow precipitated upon addition of a sol

kenny6666 [7]

<h3>Answer:</h3>

Anion present- Iodide ion (I⁻)

Net ionic equation- Ag⁺(aq) + I⁻(aq) → AgI(s)

<h3>Explanation:</h3>

In order to answer the question, we need to have an understanding of insoluble salts or precipitates formed by silver metal.

Additionally we need to know the color of the precipitates.

Some of insoluble salts of silver and their color include;

Silver chloride (AgCl) - white color
Silver bromide (AgBr)- Pale cream color
Silver Iodide (AgI) - Yellow color
Silver hydroxide (Ag(OH)- Brown color

With that information we can identify the precipitate of silver formed and identify the anion present in the sample.

The color of the precipitate formed upon addition of AgNO₃ is yellow, this means the precipitate formed was AgI.
Therefore, the anion that was present in the sample was iodide ion (I⁻).
Thus, the corresponding net ionic equation will be;

Ag⁺(aq) + I⁻(aq) → AgI(s)

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