B. The sound of the engine will get louder and the pitch higher.
Answer:
1.991 × 10^(8) N/m²
Explanation:
We are told that its volume increases by 9.05%.
Thus; (ΔV/V_o) = 9.05% = 0.0905
To find the force per unit area which is also pressure, we will use bulk modulus formula;
B = Δp(V_o/ΔV)
Making Δp the subject gives;
Δp = B(ΔV/V_o)
Now, B is bulk modulus of water with a value of 2.2 × 10^(9) N/m²
Thus;
Δp = 2.2 × 10^(9)[0.0905]
Δp = 1.991 × 10^(8) N/m²
Answer:
Assessment zone
Explanation:
It is the assessment zone in various security zones where active and passive security measures are employed to identify, detect, classify and analyze possible threats inside the assessment zones.
Your answer is infrared, visible, ultraviolet.
Answer:
answer below
Explanation:
Displacement of the student is 739 m due North and it takes 162 s.
We need to find the student's average velocity. Using formula of velocity.
Velocity = displacement/time
v= 739/162
v= 4.56
