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PSYCHO15rus [73]

3 years ago

9

Which statement correctly describes the relationship between the energy of a wave and the wave’s amplitude?

2 answers:

frez [133]3 years ago

8 0

Hi Stkdazz007,

Your Question:

Which statement correctly describes the relationship between the energy of a wave and the wave’s amplitude?

Answer:

a.High energy waves have high amplitudes.

goblinko [34]3 years ago

7 0

Answer: A)

Explanation:

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The tub of a washing machine goes into its spin cycle, starting from rest and gaining angular speed steadily for 6.00 s, at whic

MatroZZZ [7]

Answer:

$N = 42 rev$

Explanation:

As we know that initial angular speed of the tub was zero and then it increases uniformly to 4 rev/s in t = 6.00 s

so we will have

$\theta_1 = \frac{\omega_f + \omega_i}{2} t$

$\theta_1 = \frac{2\pi f_2 + 2\pi f_1}{2}(t)$

$\theta_1 = \frac{2\pi \times 4 + 0}{2}(6)$

$\theta_1 = 75.4 rad$

Now when the tub will comes to rest uniformly after opening the lid in time interval of t = 15 s

then we have

$\theta_2 = \frac{\omega_f + \omega_i}{2} t$

$\theta_2 = \frac{2\pi f_2 + 2\pi f_1}{2}(t)$

$\theta_2 = \frac{2\pi \times 4 + 0}{2}(15)$

$\theta_2 = 188.5 rad$

Now total angular displacement of the tub is given as

$\theta = \theta_1 + \theta_2$

$\theta = 75.4 + 188.5$

$\theta = 263.9 rad$

so number of revolutions is given as

$\N = \frac{\theta}{2\pi}$

$N = 42 rev$

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3 years ago

A cat dozes on a stationary merry-go-round, at a radius of 4.6 m from the center of the ride. then the operator turns on the rid

ioda

<span>Radius = 4.6 m
Time for one complete rotation t = 5.5 s.
Distance = 2 x 3.14 x R = 2 x 3.14 x 4.6 m = 28.888.
Velocity V = distance / time = 28.888 / 5.5 s = 5.25 m/s
Force exerted by cat Fc = mV^2 / R = (mx 5.25^2) / 4.6 m
Force of the cat Fc = 6m, m being the mass.
Normal force = Us x m x g = Us x m x 9.81 = Us9.81m
equating the both forces => Us9.81m = 6m => Us = 6 / 9.81 => Us = 0.6116 So coefficient of static friction = 0.6116</span>

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