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zavuch27 [327]
3 years ago
9

1.Force that pulls toward the center of mass.​

Physics
2 answers:
kondaur [170]3 years ago
7 0
Gravity if I’m not mistaken
monitta3 years ago
3 0

Gravity– a natural force that pulls objects downward. Earth's gravity pulls us and all objects downwards towards its center.

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Which best explains what happens to the motion of the pendulum?
Komok [63]
The answer is A, I just learned about this a few days ago!
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Discuss how lawmakers could use scientific knowledge to help them make decisions that would benefit society.
Anika [276]
Scientific knowledge is very firm in its facts and pieces of evidence that create a more precise definition. If lawmakers are able to use the scientific method in making a decision, it will make a big change and will be beneficial to the society. The set of rules will be more arranged, specific and restrictive that might change justice, tax, and law.
7 0
3 years ago
A 250 g air-track glider is attached to a spring with springconstant 4.0 N/m. Th damping constant due to air resistance is0.015
vaieri [72.5K]

Answer:

33.33 seconds

Explanation:

N=\dfrac{1}{e}N_0

N_0 = Initial length pulled = 20 cm

b = Damping constant = 0.015 kg/s

k = Spring constant = 4 N/m

m = Mass of glider = 250 g

Time period is given by

T=2\pi\sqrt{\dfrac{m}{k}}\\\Rightarrow T=2\pi\sqrt{\dfrac{0.25}{4}}\\\Rightarrow T=1.57079632679\ s

Using exponential decay formula

N=N_0e^{\dfrac{-bt}{m}}

Final amplitude = Initial times decay

\dfrac{1}{e}0.2=0.2e^{\dfrac{-0.015t}{2\times 0.25}}\\\Rightarrow 0.2=0.2e^{\frac{-0.015t}{2\cdot \:0.25}+1}\\\Rightarrow e^{\frac{-0.015t}{2\cdot \:0.25}+1}=1\\\Rightarrow \ln \left(e^{\frac{-0.015t}{2\cdot \:0.25}+1}\right)=\ln \left(1\right)\\\Rightarrow \left(\frac{-0.015t}{2\cdot \:0.25}+1\right)\ln \left(e\right)=\ln \left(1\right)\\\Rightarrow \frac{-0.015t}{2\cdot \:0.25}+1=\ln \left(1\right)\\\Rightarrow -\frac{0.015t}{0.5}=-1\\\Rightarrow -0.000225t=-0.0075\\\Rightarrow t=33.33\ s

The time taken is 33.33 seconds

7 0
4 years ago
A child sits on a merry-go-round, 1.5 meters from the center. The merry-go-round is turning at a constant rate, and the child is
exis [7]

Answer:

5 .07 s .

Explanation:

The child will move on a circle of radius r

r = 1.5 m

Let the velocity of rotation = v

radial acceleration = v² / r

v² / r = 2.3

v² = 2.3 r = 2.3 x 1.5

= 3.45

v = 1.857 m /s

Time of revolution = 2π r / v

= 2 x 3.14 x 1.5 / 1.857

= 5 .07 s .

5 0
3 years ago
Which of the following quantities would be acceptable representations of weight? Check all that apply.
Oxana [17]

Only 12 lb and 1600 kN .

7 0
3 years ago
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