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Sedbober [7]
3 years ago
13

Which one gives the feeling of heaviness in the case of a kilogram of cotton or a kilogram of lead? Why?​

Physics
1 answer:
brilliants [131]3 years ago
3 0

Strange as it may seem, they both give the same "feeling of heaviness".

If you put them in a pair of equal-size sealed boxes, there's no way for anyone to tell which box has the cotton and which box has the lead.

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A ball is thrown straight up from ground level. It passes a 2-m-high window. The bottom of the window is 7.5 m off the ground. T
slamgirl [31]

Answer:

u=14.48m/s

Explanation:

From the question we are told that:

Height of window h=2m

Height of window off the ground h_g=7.5m

Time to fall and drop t=1.3s

 

Generally the Newton's equation motion  is mathematically given by

 s=ut+\frac{1}{2}at^2

Where

h=ut+\frac{1}{2}at^2

2=u1.3-\frac{1}{2}*9.8*1.3^2

2=u1.3-8.281

u=7.91m/s^2  

Generally the Newton's equation motion  is mathematically given by

2as=v^2-u^2

Where

-2gh_g=v^2-u^2

-2*9.8*7.5=(7.91)^2-u^2

-147=62.5681-u^2

u=\sqrt{209.5681}

u=14.48m/s

Therefore the  ball’s initial speed

u=14.48m/s

8 0
3 years ago
a ball is projected horizontally with a velocity of 5 m per second from the top of a building 19.6 m high how long will the ball
zepelin [54]

Answer:

1.98s

Explanation:

The time taken to hit the ground is given by

h=ut+ 1/2 at^2

but u =0

so we have

h=1/2at^2

making t the subject

t=√2h/g

√2×19.6/10

1.98s

8 0
3 years ago
It is correct to say that impulse is equal toA) momentum.B) the change in momentum.C) the force multiplied by the distance the f
goldenfox [79]

Answer:

B) the change in momentum

Explanation:

Impulse is defined as the product between the force exerted on an object (F) and the contact time (\Delta t)

I=F \Delta t

Using Newton's second law (F = ma), we can rewrite the force as product of mass (m) and acceleration (a):

I=(ma) \Delta t

However, the acceleration is the ratio between the change in velocity (\Delta v) and the contact time (\Delta t): a=\frac{\Delta v}{\Delta t}, so the previous equation becomes

I=m \frac{\Delta v}{\Delta t}\Delta t

And by simplifying \Delta t,

I=m \Delta v

which corresponds to the change in momentum of the object.

8 0
3 years ago
250 mL 0.1 M HCl solution is mixed with 250 mL
pishuonlain [190]

Answer:

The concentration of OH⁻ in the mixture is 0.05 M

Explanation:

The reaction of neutralization between HCl and NaOH is the following:

H⁺(aq) + OH⁻(aq) ⇄  H₂O(l)

The number of moles of HCl is:

n_{HCl} = C*V = 0.1 mol/L*0.250L = 0.025 moles

Similarly, the number of moles of NaOH is:

n_{NaOH} = C*V = 0.2 mol/L*0.250L = 0.05 moles

Now, from the reaction of HCl and NaOH we have the following number of moles of NaOH remaining:

n_{NaOH} = 0.05 moles - 0.025 moles = 0.025 moles

Finally, the concentration of OH⁻ in the mixture is:

C =\frac{n_{NaOH}}{V_{T}}=\frac{0.025 moles}{0.250*2 L} = 0.05 moles/L

Therefore, the concentration of OH⁻ in the mixture is 0.05 M.

I hope it helps you!

8 0
3 years ago
If a 340 N girl sits on a seesaw and is lifted 1.4 m in 1.6 s, how much work was done by the child on the other side?
blondinia [14]
In physics, work is defined as the total energy when an object is moved to a certain displacement by the application of external force. It is calculated by the expression W = Fd. For this case, the displacement is apparently zero, then there is no work in the system above.
4 0
3 years ago
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