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Sedbober [7]
3 years ago
13

Which one gives the feeling of heaviness in the case of a kilogram of cotton or a kilogram of lead? Why?​

Physics
1 answer:
brilliants [131]3 years ago
3 0

Strange as it may seem, they both give the same "feeling of heaviness".

If you put them in a pair of equal-size sealed boxes, there's no way for anyone to tell which box has the cotton and which box has the lead.

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Consider a system made of a ramp that has a run of 8 m and a rise of 6 m. Two equal masses of 4-kg are connected to each other b
djyliett [7]

Answer:

The force of friction is 15.68 N.

Explanation:

Given:

Rise is 6 m and run is 8 m.

Mass of each body (m) = 4 kg

The whole system is in equilibrium.

Now, consider the diagram below representing the scenario given in the question.

The forces acting on the mass that is hanging are tension force in the upward direction and weight of the body acting vertically downward.

As the mass is in equilibrium, the total upward force equals total downward force. So,

T= mg=4\times 9.8=39.2\ N -------- (1)

Now, the forces acting on the other mass along the ramp are:

1. Tension (T) up the ramp

2. mg sin\theta and frictional force (f) down the ramp

Now, as per question:

Rise = 6 m and run = 8 m

So, from figure,

\tan\theta=\frac{6}{8}=0.75\\\\\theta=\tan^{-1}(0.75)=37\°

Now, \sin\theta=\sin(37\°)=0.6

Now, as the other mass is also at rest, net force acting on it is also 0. So,

F_{net}=0\\\\T-(mg\sin\theta+f)=0\\\\mg\sin\theta+f=T\\\\f=T-mg\sin\theta

Now, plug in the given values and solve for 'f'. This gives,

f=39.2-(4\times 9.8\times 0.6)\\\\f=39.2-23.52=15.68\ N

Therefore, the force of friction is 15.68 N

4 0
4 years ago
The hypotenuse of a right triangle is 29.0 centimeters. The length of one of its legs is 20.0 centimeters. What is the length of
Kisachek [45]

square root (29 squared - 20 squared)

Pythagoras' theorem

5 0
3 years ago
Read 2 more answers
A low C (f = 65Hz) is sounded on a piano. If the length of the piano wire is 2.0 m and its mass density is 5.0 g/m2, determine t
Pie

Answer:

338N

Explanation:

Use the formula f=\frac{\sqrt{\frac{T}{\frac{M}{L}} } }{2L}

f is the frequency, T the string tension, M the mass, and L the length

convert units to seconds, kilograms, meters

65Hz\ =\ \frac{\sqrt{\frac{T}{\frac{0.005kg}{m}}}}{2\cdot2m}

now solve for T

sqrt(T/.005) = 65*4 = 260

T = 338N

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