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Natasha2012 [34]
3 years ago
11

Debbie plotted a graph to show how the mass of aluminium rivets affected the distance the cup moved down.

Physics
1 answer:
Elan Coil [88]3 years ago
4 0

Answer:

26

Explanation:

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A 5.85-mm-high firefly sits on the axis of, and 13.7 cm in front of, the thin lens A, whose focal length is 5.01 cm. Behind lens
Alenkasestr [34]

Answer:

1. The image is real

2. 5.85

3. h' = 3.05 mm

4. The image is upright

Explanation:

1. Start with the first lens and apply 1/f = 1/p + 1/q

1/5.01 = 1/13.7 + 1/q

q = 7.90 cm

Since that distance is behind the first lens, and the second lens is 62.5 cm behind the first lens, that distance is 62.5 - 7.90 = 54.6 cm in front of the second lens, and becomes the object for that lens, thus,

1/25.9 = 1/54.6 + 1/q

q = 49.3 cm behind the second lens

Using that information, since q is positive, the image is real

2. Also, using that information, you have the second answer, which is 49.3 cm

The height can be found from the two magnifications.

m = -q/p

m1 = -7.9/13.7 = -.577

m2 = -49.3/54.6 = -.903

Net m = (-.577)(-.903) = .521

Then, m = h'/h

.521 = h'/5.85

3. h' = 3.05 mm

4. For the fourth answer, since the overall magnification is positive, the final image is upright

5 0
3 years ago
A machine does 50 J of Work on a 10 Kg Object. What is the Change in the Objects Total Energy?
Otrada [13]

The change in the total energy of the object is zero (0).

The given parameters:

work done by the machine, W = 50 J

mass of the object, m = 10 kg

To find:

the change in the total energy of the object

The change in the total energy of the object is the difference between the objects initial energy due to its position and the work done on the object.

Based on work energy-theory, the work done on the object is equal to the energy of the object.

  • The energy of the object = work-done on the object
  • The change in total energy = 50 J - 50 J = 0

Thus, the change in the total energy of the object is zero (0).

Learn more here: brainly.com/question/20377140

3 0
3 years ago
Help me, please
Mars2501 [29]
Wish I could help you you rock
6 0
3 years ago
1. Draw magnetic field (B field) line diagrams for the following. Make sure the diagrams are large enough so the direction and s
larisa [96]

I attached the requested diagram.

<em>In the case of the magnetic field in a bar</em> by convention, the direction of the field is taken out of the north pole and towards the south pole of the magnet. These types of images are commonly made of some ferrous material.

<em>In the case of the horseshoe </em>magnet, the highly concentrated magnetic field is distinguished between its legs. In the figure it is shown in a contribution from North to South, again by agreement, however outside the two poles, the magnetic field falls rapidly. A horseshoe magnet is basically a bent bar magnet.

4 0
3 years ago
Displacement vector of 4 km north, 2 km south, 5 km north, and 5km south combine to a total displacement of ? A 2 km South b 16
Andrews [41]
It is C. 16 km north. 
3 0
4 years ago
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