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const2013 [10]
3 years ago
7

Explain how you would draw magnetic field lines in the vicinity of this magnet (it is a normal north and south magnet)

Physics
1 answer:
sammy [17]3 years ago
3 0
Can someone please answer this question I'm doing the test now?
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What is Newton's Second Law?
Rudiy27

Answer:

An object's acceleration depends on its mass and on the net force acting on it.

Explanation:

Newton's second law states that the acceleration of an object is directly related to the net force and inversely related to its mass. Acceleration of an object depends on two things, force and mass.

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The -is the process by which gases in the atmosphere absorb and reradiate heat?
Nikolay [14]
Water vapor and carbon dioxide

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3 years ago
Select the correct answer.
skelet666 [1.2K]

Answer:

B is the best answer for the question

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A student is swimming south applying a force of 256 N. The water exerts a westward force of 104 N. If the student has a mass of
grigory [225]

Answer:

a=2.9\ m/sec^2

Explanation:

<u>Net Forces and Acceleration</u>

The second Newton's Law relates the net force F_r acting on an object of mass m with the acceleration a it gets. Both the net force and the acceleration are vector and have the same direction because they are proportional to each other.

\vec F_r=m\vec a

According to the information given in the question, two forces are acting on the swimming student: One of 256 N pointing to the south and other to the west of 104 N. Since those forces are not aligned, we must add them like vectors as shown in the figure below.

The magnitude of the resulting force F_r is computed as the hypotenuse of a right triangle

|F_r|=\sqrt{256^2+104^2}

|F_r|=276.32\ Nw

The acceleration can be obtained from the formula

F_r=ma

Note we are using only magnitudes here

\displaystyle a=\frac{F_r}{m}

\displaystyle a=\frac{276.32Nw}{95.3Kg}

\boxed{a=2.9\ m/sec^2}

7 0
3 years ago
A cube made Of an unknown material has a height of 9 symeters the mass of this cube is 3645 g. calculate the density of this cub
kherson [118]

Answer: 5 \frac{g}{cm^{3}}

Explanation:

The density \rho of a material is given by:

\rho=\frac{m}{V} (1)

Where:

m=3645 g is the mass of the cube

V is the volume of the cube

Now, the volume of a cube is equal to the length L of its edge to the power of 3:

V=L^{3} (2)

If we know L=9 cm, the volume of this cube is:

V=(9 cm)^{3}=729 cm^{3} (3)

Substituting (3) in (1):

\rho=\frac{3645 g}{729 cm^{3}} (4)

\rho=5 \frac{g}{cm^{3}} This is the density of the cube

8 0
3 years ago
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