TLDR: R=30 Ohms, I=2 Amps, 12V, 28V, 20V, respectively.
Alright, let’s break this down. There are three resistors in this circuit, meaning that we have to find the equivalent resistance. Luckily, they are all in parallel with one another; this means we can add the resistances together without having to do inverses like in a series problem. This means that the equivalent resistance, Req, would equal:
Req=R1 + R2 + R3
Req=6 + 14+ 10
Req=30 Ohms
This means that we could theoretically replace all three resistors with a 30 Ohm resistor and accomplish the same goal. Now, the entire voltage of the system would normally be reduced to zero after passing through the resistors - in this case, the 60 Vs would be lost after passing through 30 Ohms. This means we’re losing 2V/Ohm; now we can figure out how much we’re losing at each resistor.
By losing 2V per Ohm, we’re losing 12 V at the first resistor, 28 V at the second resistor, and 20 V at the third resistor.
Finally, we can calculate the current through the circuit; for a series circuit, the current remains the same. Using V=IR, we can find that:
V=IR
60 V = I(30 Ohms)
I = 2 Amps
The current passing through the circuit is 2 Amps.
Hope this helps!
The unit for measuring the rate at which light is radiated from a source is B, Lumen. Lumenous flux is the time rate of the flow of light, or the visible energy produced from a certain light source. It is the quantitative measure of brilliance of a light source. The unit we use for this is lumen.
i squared r = 0.03x0.03x1000=3x0.03x10=.9W
Figure A shows cross section of a land form or rock. In Figure B, compression stress is applied on it. When compression stresses are applied on a rock, it squeezes the rock cause fold or fracture. The fault formed by compression stress is called thrust fault. If the compression stresses/ force continue to act on a rock it will converge and form thrust fault. In Figure C, tension stresses is applied on the rock. When a tension stress applied on a rock it deforms/ lengthen. There are three type of deformations occur due to tension stresses. One is elastic deformation, in which, rock retains it original shape when force/stresses are removed. Second is plastic deformation, in which rock lengthen and change occur permanently. Third type of deformation is result into fracture or breaking of rock. In Figure C, shear stresses are applied on rock. Shear stresses are applied with equal magnitude but in opposite direction. It cause breaking of rock.
