Answer:
2. mechanical weathering can produce smaller pieces of rock that have more surface area for chemical weathering to work Explanation:
Mechanical weathering involves activities of living organisms or some geological processes. The bigger rocks are usually reduced to smaller rocks and further reduction might be limited or not posibble mechanically. This reduced rocks now increases the surface area available for chemical weathering; which further reduces the sizes of the rocks below the size range of mechanical weathering. one will recall that the rate of chemical reaction increases with exposed surface area.
A=pi r^2
A=( 3.14159.......)(12.77)^2
A= 512.30m^2
This information could be used in the following ways: the braking distance of a skidding car will depend on its initial speed and the coefficient of kinetic friction.
Thus, if the coefficient of friction is known the initial speed can be determined from the length of the skid marks.
What do you mean by Initial speed?
Initial speed can be described as how fast an object travels when gravity first applies force on the object. It can be represented in the form of (u) and is generally measured in metres per second (m/s).
It can be represented in three ways.
- v2=u2+2as
- v=u+at
- s=ut+0.5at2
Through these formulas we can calculate the initial speed of any object. It helps in understanding various velocities, time principles.
To know more about initial speed from the given link
brainly.com/question/26116359
#SPJ4
Answer:
Both technicians are correct
Explanation:
Because we are talking about a series circuit, both technicians are correct.
- <u>The total resistance of a series circuit is equal to the sum of each of all the individual resistances that make up the series circuit</u>, just as technician A says.
- And similarly <u>when adding the voltage in each of the resistences or components of the series circuit it should be equal to the source voltage</u>, the voltage supplied to the circuit, which is what Technician B says.
For these reasons the answer is that both A and B are correct.
