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dlinn [17]
3 years ago
9

Which is more soluble at 28

Chemistry
2 answers:
CaHeK987 [17]3 years ago
3 0

Answer:

a.

Explanation:

At 28 degrees highest line is CaCl2. Answer a.

Lelu [443]3 years ago
3 0
I think it’s A I could be wrong
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3 years ago
Reaction of hypochlorous acid and ammonia is product-favored system at equilibrium. Answer A: Reaction of hypochlorous acid and
pickupchik [31]

Answer:

A. True

B. False

Explanation:

Reaction between hypochlorous acid and ammonia does not yields a Ph value of 7.00 , this value is defined to water and no other reaction can yield exactly this Ph value. The acid reaction will give a Ph value below 7 while a base reaction will give Ph value of above 7.

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2 years ago
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Arada [10]
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6 0
3 years ago
The atomic number of Re is 75. The atomic mass of one of its isotopes is 186. How many neutrons are in an atom of this isotope?
USPshnik [31]

Answer:

B.111

Explanation:

Atomic mass = number of protons(or atomic number) + number of neutrons

186 = 75 + number of neutrons

number of neutrons = 186 -75 = 111

7 0
3 years ago
In the following reaction, how many moles of CO2 will form if 10 moles of C3H4 are reacted? How many moles of O2 will also be co
umka2103 [35]

Answer:

40 moles of O₂

30 moles of CO₂

Explanation:

Given parameters:

Number of moles of C₃H₄  = 10moles

Unknown:

Number of moles of CO₂ = ?

Solution:

The number of moles helps to understand and make quantitative measurements involving chemical reactions.

We start by solving this sort of problem by ensuring that the given equation is properly balanced;

        C₃H₄    +      4O₂    →     3CO₂     +      2H₂O

We can clearly see that all the atoms are conserved.

Now, we work from the known to unknown. We know the number of moles of  C₃H₄ to be 10moles;

             1 mole of  C₃H₄ reacted with 4 moles of O₂

              10 moles of C₃H₄ will react with 10 x 4 = 40moles of O₂

      1 mole of  C₃H₄ will produce 3 moles of CO₂

       10 moles of C₃H₄ will produce 10 x 3 = 30moles of CO₂

   

4 0
3 years ago
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