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dlinn [17]
3 years ago
9

Which is more soluble at 28

Chemistry
2 answers:
CaHeK987 [17]3 years ago
3 0

Answer:

a.

Explanation:

At 28 degrees highest line is CaCl2. Answer a.

Lelu [443]3 years ago
3 0
I think it’s A I could be wrong
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Wind is related to the movement of warm and cold air masses. Which kind of heat transfer does this represent?
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I assume you meant to write convection for one of those answers. Convection is the way that heat is transferred through liquids and gases.
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4 years ago
A particular beer is 65.0% ethanol by volume . If a single bottle of beer contains a total of 750.0 mL of beer, what volume, in
Oksi-84 [34.3K]

The volume in mL of ethanol (C₂H₆O) present in the bottle is 487.5L

HOW TO CALCULATE VOLUME OF ETHANOL:

  • According to this question, a particular beer is 65.0% ethanol by volume. This means that the beer contains 65/100 of ethanol.

  • If a single bottle of beer contains a total of 750.0 mL of beer, the volume of ethanol in the bottle is calculated as follows:

  • = 65/100 × 750

  • = 65 × 7.5

  • = 487.5mL

  • Therefore, volume in mL of ethanol (C₂H₆O) present in the bottle is 487.5L

Learn more at: brainly.com/question/8725232?referrer=searchResults

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The conversion of glucose-6-phosphate to fructose-6-phosphate is catalyzed by an isomerase enzyme. Glucose-6-phosphate was mixed
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Answer: the equilibrium is 0.667 M

5 0
4 years ago
How would you find the atomic number, atomic mass, protons, neutrons and electrons for ions and isotopes? Is it similar?
cricket20 [7]

Atomic number = number of protons

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7 0
3 years ago
NEED HELP ASAP NOT DIFFICULT
Burka [1]
Answer- 400 grams of AlCl3 is the maximum amount of AlCl3 produced during the experiment.

Given - Number of moles of Al(NO3)3 - 4 moles
Number of moles of NaCl - 9 moles
Find - Maximum amount of AlCl3 produced during the reaction.
Solution - The complete reaction is - Al(NO3)3 + 3NaCl --> 3NaNO3 + AlCl3
To find the maximum amount of AlCl3 produced during the reaction, we need to find the limiting reagent.
Mole ratio Al(NO3)3 - 4/1 - 4
Mole ratio NaCl - 9/3 - 3
Thus, NaCl is the limiting reagent in the reaction.
Now, 3 moles of NaCl produces 1 mole of AlCl3
9 moles of NaCl will produce - 1/3*9 - 3 moles.
Weight of AlCl3 - 3*133.34 - 400 grams
Thus, 400 grams of AlCl3 is the maximum amount of AlCl3 produced during the experiment.
5 0
3 years ago
Read 2 more answers
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