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laila [671]
3 years ago
5

What happens to the H20 in a combustion reaction?

Chemistry
1 answer:
allochka39001 [22]3 years ago
6 0

A combustion reaction is when a substance reacts with oxygen and releases a huge amount of energy in the form of light and heat. A combustion reaction always has oxygen as one reactant. ... A combustion reaction also always produces CO2 and H2O.

So water (H2O) is created

Source: https://study.com/academy/lesson/writing-and-balancing-combustion-reactions.html

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g in the combustion of 0.398 mol c4h8, how many moles of o2 would be required to completely react with the fuel?
storchak [24]

41.4 grams of oxygen is essentially required for complete combustion of 3 moles of butane gas.

<h3>What is combustion?</h3>
  • Combustion is a chemical reaction that often involves the presence of oxygen and produces heat and light in the form of flames.
  • Because of the nature of the chemical reaction and the fact that more energy is produced than can be released into the surrounding medium, the rate or speed at which the reactants combine is high.
  • As a result, the temperature of the reactants is increased, accelerating the process even further.

As you know, combustion reaction is a chemical reaction in which a substance reacts with the atmospheric oxygen (O₂) to produce carbon dioxide and water. Therefore, balanced combustion reaction of butane (C₄H₁₀) will be as follows:

C₄H₁₀+\frac{13}{2}O₂→4CO₂+5H₂O

You can observe in the above reaction that, \frac{13}{2} moles of oxygen are required for combustion of 1 mole of butane.

Therefore, going by unitary method, for complete combustion of 3 moles of butane, (\frac{13}{2}×0.398) moles of oxygen would be required.

Now, we know, number of moles = \frac{Given mass}{Molar mass}

Molar mass of oxygen is 16 g/mol

We need to find a given mass which is the mass of oxygen required when the number of moles is equal to 2.59.

Thus, given mass of oxygen or mass of oxygen required = number of moles of oxygen × molar mass of oxygen

Mass of oxygen required = 2.59 moles × 16 g/mol = 41.4 g.

Hence, 41.4 grams of oxygen is essentially required for complete combustion of 3 moles of butane gas.

To learn more about combustion, refer to

brainly.com/question/13251946

#SPJ4

8 0
1 year ago
A balloon is inflated to a volume of 7.0 L 7.0 L on a day when the atmospheric pressure is 765 mmHg. The next day, as a storm fr
kirill115 [55]

Answer:

The new volume is 7.27 L

Explanation:

Step 1: Data given

The initial volume of the balloon = 7.0 L

The pressure = 765 mmHg = 765/760 atm = 1.00658 atm

The pressure drops to 737 mmHg = 737/ 760 atm = 0.969737

The temperature remains constant

Step 2: Calculate the new volume

P1*V1 = P2*V2

⇒with P1 = the initial pressure in the balloon = 765 mmHg

⇒with V1 = the initial volume = 7.0L

⇒with P2 = the decreased pressure = 737 mmHg

⇒with V2 = the new volume = TO BE DETERMINED

765 mmHg * 7.0 L = 737 mmHG * V2

V2 = (765 mmHG * 7.0 L) / 737 mmHG

V2 = 7.27 L

The new volume is 7.27 L

6 0
3 years ago
Which is the BEST example of refraction?
Fudgin [204]
C) A laser beam looks bent when it passes through glass blocks.

Hope this helps!
5 0
3 years ago
Read 2 more answers
Backpackers often use canisters of white gas to fuel a cooking stove’s burner. If one canister contains 1.45 L of white gas, and
rusak2 [61]
1 L ------- 1000 cm³
1.45 L ----- ???

1.45 * 1000 = 1450 cm³  ( volume ) 

Density = 0.710 g/cm³

mass =  in Kg 

m = D * V

m = 0.710  * 1450

m = 1029.5 g

1 Kg ------- 1000 g
   kg -------- 1029.5 g

mass = 1029.5 / 1000

mass = 1.0295 Kg

hope this helps!

7 0
3 years ago
<img src="https://tex.z-dn.net/?f=%20%5Cfrac%7B1%7D%7B5%7D%20%2B%20%20%5Cfrac%7B2%7D%7B5%7D%20" id="TexFormula1" title=" \frac{1
Travka [436]
3/4 cause its addition
8 0
3 years ago
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