What happens to the H20 in a combustion reaction?

1 answer:

6 0

A combustion reaction is when a substance reacts with oxygen and releases a huge amount of energy in the form of light and heat. A combustion reaction always has oxygen as one reactant. ... A combustion reaction also always produces CO2 and H2O.

So water (H2O) is created

Source: https://study.com/academy/lesson/writing-and-balancing-combustion-reactions.html

You might be interested in

Why do substances with weak intermolecular forces form solids at low melting points?

Advocard [28]

To make any substance solid, molecules must come very close to each other. Substances with weak intermolecular forces have weak bonding. Hence to make their molecules come close to each other, we must provide low temperature.

7 0

2 years ago

Question 5

Stolb23 [73]

Answer:

There are 17.64% students received B+ grades.

Explanation:

It is given that,

Total number of students in chemistry class is 17

We need to find the percentage received by B+.

Number of students having B+ grades are 3 (from graph)

Required percentage = $P=\dfrac{3}{17}\times 100=17.64\%$

So, there are 17.64% students received B+ grades.

8 0

2 years ago

What is the balanced form of the chemical equation shown below?<br> N2(g) + H2(g) → NH3(g)<br> -

Rom4ik [11]

To balance equations you have to have same number of atoms on both sides of the equation just multiply with a suitable digit

6 0

1 year ago

HBr + H₂SO₄ SO₂ + Br₂ + H₂O<br><br> whats the oxidizing agent and whats the reducing agent?

seropon [69]

Answer:

HBr + H₂SO₄ → SO₂ + Br₂ + H₂O An oxidizing agent is a substance that itself becomes reduced and oxidizes the other chemical species in the reaction mixture. A reducing agent is similar, except that it becomes oxidized and reduces the other substance. In the reaction, the valency of bromine changes from -1 to 0, so it is oxidized

Explanation:

3 0

2 years ago

Read 2 more answers

Consider the combustion of h2(g) 2h2(g)+o2(g)→2h2o(g). If hydrogen is burning at the rate of 0.49 mol/s, what is the rate of con

mamaluj [8]

Answer : The rate of consumption of oxygen = 0.245 mol/s

Solution : Given,

Rate at which Hydrogen burns = 0.49 mol/s

The Reaction is,

$2H_{2}(g)+O_{2}(g)\rightarrow 2H_{2}O(l)$