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Natali5045456 [20]
3 years ago
6

What words from the vocabulary that is on the bottom left corner go in number 4-8?

Physics
1 answer:
Helen [10]3 years ago
5 0

Answer:

4) Inner Core

5) Outer Core

6)Crust

7) Convection

8)   Volcanoes    

Explanation:

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1
marishachu [46]

Answer: B

Explanation:

4 0
3 years ago
how is the acceleration of a car traveling on an elevated air track related to the angle of elevation
quester [9]
Acceleration is a vector quantity that expresses the rate of change in velocity. Being a vector quantity, then the value has magnitude and direction. If the car exerts a constant net force as it travels, the greater the angle of elevation is, the greater is the decrease in its acceleration. Since the vertical component of is affected by the acceleration due to the gravity, that is why vehicles exert more force to climb a steeper hills. 
5 0
3 years ago
If the speed of light in a substance is 2.26 x 10^8 m/s, what is the index of refraction of that substance?
vladimir1956 [14]

Answer:

1.33

Explanation:

speed of light in vacuum, c = 3 x 10^8 m/s

speed of light in medium, v = 2.26 x 10^8 m/s

The refractive index of the medium is given by

μ = speed of light in vacuum / speed of light in medium

μ = (3 x 10^8) / (2.26 x 10^8)

μ = 1.33

4 0
3 years ago
A satellite is always being pulled by gravity.<br> a. True<br> b. False
tangare [24]
This is true. Gravity is constantly pulling on anything and everything (even light!), no matter how far away it is from another object.
3 0
3 years ago
Someone please help with this
SSSSS [86.1K]

Answer:

<em>The new force is 2/3 of the original force</em>

Explanation:

<u>Coulomb's Law </u>

The electrical force between two charged objects is directly proportional to the product of their charges and inversely proportional to the square of the distance between the two objects.

Written as a formula:

\displaystyle F=k\frac{q_1q_2}{d^2}

Where:

k=9\cdot 10^9\ N.m^2/c^2

q1, q2 = the objects' charge

d= The distance between the objects

Suppose the first charge is doubled (2q1) and the second charge is one-third of the original charge (q2/3). Now the force is:

\displaystyle F'=k\frac{2q_1*q_2/3}{d^2}

Factoring out 2/3:

\displaystyle F'=\frac{2}{3}k\frac{q_1*q_2}{d^2}

Substituting the original force:

F'=\frac{2}{3}F

The new force is 2/3 of the original force

7 0
3 years ago
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