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Natali5045456 [20]
3 years ago
6

What words from the vocabulary that is on the bottom left corner go in number 4-8?

Physics
1 answer:
Helen [10]3 years ago
5 0

Answer:

4) Inner Core

5) Outer Core

6)Crust

7) Convection

8)   Volcanoes    

Explanation:

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An object is moving in the plane according to these parametric equations:
aniked [119]
A. The horizontal velocity is 
vx = dx/dt = π - 4πsin (4πt + π/2)
vx = π - 4π sin (0 + π/2)
vx = π - 4π (1)
vx = -3π

b. vy = 4π cos (4πt + π/2)
vy = 0

c. m = sin(4πt + π/2) / [<span>πt + cos(4πt + π/2)]

d. m = </span>sin(4π/6 + π/2) / [π/6 + cos(4π/6 + π/2)]

e. t = -1.0

f. t = -0.35

g. Solve for t 
vx = π - 4πsin (4πt + π/2) = 0
Then substitute back to solve for vxmax

h. Solve for t
vy = 4π cos (4πt + π/2) = 0
The substitute back to solve for vymax

i. s(t) = [<span>x(t)^2 + y</span>(t)^2]^(1/2)

h. s'(t) = d [x(t)^2 + y(t)^2]^(1/2) / dt

k and l. Solve for the values of t
d [x(t)^2 + y(t)^2]^(1/2) / dt = 0
And substitute to determine the maximum and minimum speeds.
5 0
3 years ago
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As resistance goes up, what happens to the current?
Dmitriy789 [7]
I=U/R
As resistance goes up, current is goes down
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4. What impact will it have to a forest ecosystem if large number of tiger<br>are introduced?<br>​
gulaghasi [49]

Think as it real and answer

4 0
3 years ago
A loaded ore car has a mass of 950 kg and rolls on rails with negligible friction. It starts from rest and is pulled up a mine s
Ierofanga [76]

Answer:

a). P=11.04kW

b). Pmax=11.38 kW

c). Wt=6423.166kJ

Explanation:

The power of the motor when the speed is constant is the work in a determinate time.

P=\frac{W}{t}

The work is the force the is applicated in a distance so

W=F*d

replacing:

P=F*\frac{d}{t} and \frac{d}{t} determinate distance in time is velocity so

a).

P=F*v

F=m*a\\F=m*g*sin(33.5)

P=950kg*9.8\frac{m}{s^{2}}*sin(33.5)*2.15\frac{m}{s}\\P=11047.846 W\\P=11.0478 kW

b).

The maximum power must the motor provide, is the maximum force with the maximum speed of the motor in this case

The first step is find the acceleration so

vi=0\frac{m}{s} \\vf=2.15 \frac{m}{s}\\vf=vi+a*t\\vf-vi=a*t\\ a=\frac{vf-vi}{t}= a=\frac{2.15\frac{m}{s}-0\frac{m}{s}}{13s}\\a=0.1653 \frac{m}{s^{2}}

The maximum force is when the car is accelerating so

Ft=Fa+Fg\\Ft=m*a+m*g*sin(33.5)\\Ft=950kg*0.1653\frac{m}{s^{2}}+950*9.8\frac{m}{s^{2}}*sin(33.5)\\Ft=5295.565 N

so the maximum force is the maximum force by the maximum speed

Pmax=Ft*v\\Pmax=5295.565N*2.15\frac{m}{s}\\Pmax=11385.46\\Pmax=11.3854kW

c).

The total energy transfer without any friction is the weight move in the high axis y in this case, so is easy to know that distance

W=m*g*h

h=Length*sin(33.5)

W=m*g*Length*sin(33.5)

W=950 kg*9.8* 1250m*sin(33.5)

W=6423166.667 kJ

W=6423.166 kJ

4 0
3 years ago
Can someone plz help me ASAP
d1i1m1o1n [39]

Answer:

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