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Mariulka [41]
3 years ago
10

Need physics help ASAP please taking test

Physics
2 answers:
sattari [20]3 years ago
5 0

Answer:

the answer is d :)

Explanation:

AlladinOne [14]3 years ago
3 0
I think it’s D too but I’m not fully sure but good luck!!
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A chemist needs to order an element that will not react with any other element. Which element should he order
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Helium

Explanation:

Helium is the least reactive element, since it is a noble gas with the smallest amount of valence rings.

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What are atoms and molecules constantly doing?
Alexus [3.1K]

A. molecules are CONSTANTLY moving.

7 0
3 years ago
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A cable is wrapped several times around a uniform solid cylinder with diameter 0.12 m and mass
Naya [18.7K]

Answer:

Which of the following was not a reaction to John Brown's execution because of his failed raid on Harper's Ferry ???????

Explanation:

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3 years ago
The component of the external magnetic field along the central axis of a 78-turn circular coil of radius 34.0 cm decreases from
grigory [225]

Answer:

Induced current, I = 18.88 A

Explanation:

It is given that,

Number of turns, N = 78

Radius of the circular coil, r = 34 cm = 0.34 m

Magnetic field changes from 2.4 T to 0.4 T in 2 s.

Resistance of the coil, R = 1.5 ohms

We need to find the magnitude of the induced current in the coil. The induced emf is given by :

\epsilon=-N\dfrac{d\phi}{dt}

Where

\dfrac{d\phi}{dt} is the rate of change of magnetic flux,

And \phi=BA

\epsilon=-NA\dfrac{dB}{dt}

\epsilon=-78\times \pi (0.34)^2\dfrac{(0.4-2.4)}{2}

\epsilon=28.32\ V

Using Ohm's law, \epsilon=I\times R

Induced current, I=\dfrac{\epsilon}{R}

I=\dfrac{28.32}{1.5}

I = 18.88 A

So, the magnitude of the induced current in the coil is 18.88 A. Hence, this is the required solution.

5 0
3 years ago
– A man walks 50 meters due west, then 50 meters 60 north of west. Determine the magnitude and direction of the resultant disp
Fynjy0 [20]

Answer:

86.6, 45°

Explanation:

The diagram explains better.

Using vector component method:

We find the x and y components of the vectors :

For the first:

A = -50cos(0)i + 50sin(0)j

A = -50i

For the second:

B = -50cos(60)i + 50sin(60)j

B = -25i + 43.3j

The resultant vector is :

R = A + B

R = -50i - 25i + 43.3j

R = -75i + 43.3j

The magnitude is:

R = [(-75)² + (43.3)²]^½

R = 86.6m

The angle is

tanθ = (50/50) = 1

θ = 45°

5 0
3 years ago
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