The best way for the microscopic comparison of paint chips is the standard infrared spectroscopy technique.
<u>Explanation:
</u>
The hit and run road accidents often leave paint chips with which the forensic investigation is conducted and the complete incident is recalled. The paint chips are actually multi-layered materials with several coats of paints.
The best way to make a microscopic comparison of paint chips, infrared microscopes are used which provide spectra for each of the existing layer.
There are three main sampling techniques in the infrared spectroscopy such as Transmission, Attenuated Total Reflectance (ATR) and the specular reflectance. With this technique, scientists can better judge the consequences of the incident and provide better proofs of the crime.
Australia separated from other continents and species there evolved independently
Explanation
Resonance:
1. The amplitude of vibration is very large.
2. The vibrations of the body are in phase with the external periodic force.
Forced Vibrations:
1. The amplitude of vibration is usually small.
2. The vibrations of the body are not in phase with the external periodic force.
Answer:
q = 0.0392 / V, for V= 0.1V q = 0.392 C
Explanation:
For this exercise we can assume that the power energy of the drops is transformed into kinetic energy, therefore we use the conservation of energy
starting point
Em₀ = U = q V
final point
Em_f = K = ½ m v²
Em₀ = Em_f
q V = ½ m v²
q =
let's calculate
q = ½ 0.40 10⁻³ 14² / V
q = 0.0392 / V
The object to be painted is connected to ground therefore its potential is dro, but the gun where it is painted has a given potential, suppose it is
V = 0.1 V
q = 0.0392 / 0.1
q = 0.392 C
Answer:
(B) The total internal energy of the helium is 4888.6 Joules
(C) The total work done by the helium is 2959.25 Joules
(D) The final volume of the helium is 0.066 cubic meter
Explanation:
(B) ∆U = P(V2 - V1)
From ideal gas equation, PV = nRT
T1 = 21°C = 294K, V1 = 0.033m^3, n = 2moles, V2 = 2× 0.033=0.066m^3
P = nRT ÷ V = (2×8.314×294) ÷ 0.033 = 148140.4 Pascal
∆U = 148140.4(0.066 - 0.033) = 4888.6 Joules
(C) P2 = P1(V1÷V2)^1.4 =148140.4(0.033÷0.066)^1.4= 148140.4×0.379=56134.7 Pascal
Assuming a closed system
(C) Wc = (P1V1 - P2V2) ÷ 0.4 = (148140.4×0.033 - 56134.7×0.066) ÷ 0.4 = (4888.6 - 3704.9) ÷ 0.4 = 1183.7 ÷ 0.4 = 2959.25 Joules
(C) Final volume = 2×initial volume = 2×0.033= 0.066 cubic meter