The deceleration of the rocket sled if it comes to rest in 1.1 s from a speed of 1000 km/h is 
.
The acceleration in opposite direction is known as the deceleration. Basically the deceleration is negative value of the acceleration since the negative sign depicts its opposite in direction.
The given data:
time, t = 1.1 s
initial speed, u = 1000 km/h = 
final speed, v = 0 m/s
So we will be using the equation of motion, that is,
v = u + at
Hence , the deceleration of the rocket is .
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1(km)cubed = (1,000 m) x (1,000 m) x (1,000 m) = 1 billion cubic meters
1.4 x 10 to the 9 cubic km = 1.4 x 10 to the 9 x (10 to the 9 cubic meters) =
1.4 x 10 to the 18 cubic meters.
The law applied here is Hooke's Law which describes the force exerted by the spring with a given distance. The equation for this is F = kΔx, where F is the force in Newtons, k is the spring constant in N/m while Δx is the displacement in meters.
If you want to find work done by a spring, this can be solved by using differential equations. However, derived equations are already ready for use. The equation is
W = k[{x₂-x₁)² - (x₁-xn)²],
where
xn is the natural length
x₁ is the stretched length
x₂ is also the stretched length when stretched even further than x₁
In this case xn =x₁. So, that means that (x₁-xn) = 0 and (x₂-x₁) = 11 cm or 0.11 m.
Then, substituting the values,
2 J = k (0.11² -0²)
k = 165.29 N/m
Finally, we use the value of k to the Hooke's Law to determine the Force.
F = kΔx = (165.29 N/m)(0.11 m)
F = 18.18 Newtons
Answer:
6.48 m/s
Explanation:
We are given that
Mass,M=2 kg
Radius,R=0.25 m
Height,h=3 m
Moment of inertia of solid sphere=
We have to find the linear speed.
By law of conservation of energy
Where 
Substitute the values
