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Lapatulllka [165]
3 years ago
13

Explain, in detail, how you convert grams of one substance to grams of something else. Be specific and include each step

Chemistry
1 answer:
mariarad [96]3 years ago
4 0
Given the mass (in grams) of a reactant A, first divide this by the molar mass of A to get the number of moles of A. Then balance the chemical reaction, and divide the number of moles of A by the coefficient of A in the balanced reaction. Next, find the coefficient of the product (B) in the reaction, and multiply this by the result from the previous operation. Finally, multiply by the molar mass of B to get the final answer in grams of the product B.
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A discus thrower throws a 1.6kg discus at 25m/s what's the kinetic energy?​
Ilya [14]

Answer:

<h2>500 J</h2>

Explanation:

The kinetic energy of an object can be found by using the formula

k =  \frac{1}{2} m {v}^{2} \\

where

m is the mass

v is the velocity

From the question

m = 1.6 kg

v = 25 m/s

We have

k =  \frac{1}{2}  \times 1.6 \times  {25}^{2}  \\  = 0.8 \times 625 \\  = 500

We have the final answer as

<h3>500 J </h3>

Hope this helps you

6 0
3 years ago
What mass of nitrogen is needed to fill an 855 L tank at STP?
scoundrel [369]

Answer:

It takes 1,068.76 grams of nitrogen to fill an 855 L tank at STP.

Explanation:

The STP conditions refer to the standard temperature and pressure. Pressure values at 1 atmosphere and temperature at 0 ° C or 273.15 °K are used and are reference values for gases.

On the other side, the pressure, P, the temperature, T, and the volume, V, of an ideal gas, are related by a simple formula called the ideal gas law:  

P*V = n*R*T

where P is the gas pressure, V is the volume that occupies, T is its temperature, R is the ideal gas constant, and n is the number of moles of the gas.

So, in this case:

  • P= 1 atm
  • V= 855 L
  • n= ?
  • R= 0.082 \frac{atm*L}{mol*K}
  • T= 273.15 K

Replacing:

1 atm* 855 L= n* 0.082 \frac{atm*L}{mol*K} * 273.15 K

Solving:

n=\frac{1 atm* 855 L}{0.082\frac{atm*L}{mol*K} *273.15 K }

n= 38.17 moles

Being the molar mass of nitrogen N2 equal to 28 g / mol, you can apply the following rule of three: if there are 28 grams in 1 mole, how much mass is there in 38.17 moles?

mass=\frac{38.17 moles*28 grams}{1 mole}

mass= 1,068.76 grams

<u><em> It takes 1,068.76 grams of nitrogen to fill an 855 L tank at STP.</em></u>

3 0
3 years ago
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