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vodomira [7]
4 years ago
12

Nc3

Engineering
1 answer:
Masja [62]4 years ago
3 0

please give a better explanation of what you want to be answered.

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An American architect whose principles of building included consonance with the landscape was ____________________________.
scoundrel [369]

An American architect whose principles of building included consonance with the landscape was:

  • Frank Lloyd Wright

<h3>Who was Frank Lloyd Wright?</h3>

Frank Lloyd Wright was an American architect who lived between 1867 to 1959. One of the notable features of his prairie houses was their ability to rhyme with the Chicago landscape.

The Unity Park in Illinois and the Hillside Home School in Wisconsin were some structures that he erected.

Learn more about Frank Lloyd Wright here:

brainly.com/question/24196635

#SPJ4

7 0
2 years ago
A turntable A is built into a stage for use in a theatrical production. It is observed during a rehearsal that a trunk B starts
lions [1.4K]

Answer:

The coefficient of static friction, μₛ, between the trunk and turntable = 0.32

Explanation:

For this motion of the trunk B,

Initial velocity, v₀ = 0

Tangential Acceleration, a = 0.28 m/s²

Time taken, t = 10s

Using equations of motion,

v = v₀ + at

v = 0 + 0.28 × 10 = 2.8 m/s

Frictional force, Fᵣ = μₛN

μₛ = coefficient of static friction,

N = Normal reaction exerted on the trunk B as a result of its weight = mg

Doing a force balance on the trunk B,

Force keeping the trunk B in circular motion must balance the frictional forces.

Force keeping the trunk B in circular motion, F = mv²/r

Fᵣ = F

μₛN = mv²/r but N = mg

μₛmg = mv²/r

μₛg = v²/r

μₛ = v²/gr

μₛ = 2.8²/(9.8 × 2.5) = 0.32

Hope this helps!!!

3 0
3 years ago
The time delay of a long-distance call can be determined by multiplying a small fixed constant by the number of communication li
aliina [53]

Answer:

We can compute the diameter of the tree T by a pruning procedure, starting at the leaves (external nodes).

  • Remove all leaves of T. Let the remaining tree be T1.
  • Remove all leaves of T1. Let the remaining tree be T2.
  • Repeat the "remove" operation as follows: Remove all leaves of Ti. Let remaining tree be Ti+1.
  • When the remaining tree has only one node or two nodes, stop! Suppose now the remaining tree is Tk.
  • If Tk has only one node, that is the center of T. The diameter of T is 2k.
  • If Tk has two nodes, either can be the center of T. The diameter of T is 2k+1.

Explanation:

We can compute the diameter of the tree T by a pruning procedure, starting at the leaves (external nodes).

  • Remove all leaves of T. Let the remaining tree be T1.
  • Remove all leaves of T1. Let the remaining tree be T2.
  • Repeat the "remove" operation as follows: Remove all leaves of Ti. Let remaining tree be Ti+1.
  • When the remaining tree has only one node or two nodes, stop! Suppose now the remaining tree is Tk.
  • If Tk has only one node, that is the center of T. The diameter of T is 2k.
  • If Tk has two nodes, either can be the center of T. The diameter of T is 2k+1.
4 0
4 years ago
Can a 1½ " conduit, with a total area of 2.04 square inches, be filled with wires that total 0.93 square inches if the maximum f
Papessa [141]

Answer:

it is not possible to place the wires in the condui

Explanation:

given data

total area = 2.04 square inches

wires total area = 0.93 square inches

maximum fill conduit =  40%

to find out

Can it is possible place wire in conduit conduit

solution

we know maximum fill is 40%

so here first we get total area of conduit that will be

total area of conduit = 40% × 2.04

total area of conduit = 0.816 square inches

but this area is less than required area of wire that is 0.93 square inches

so we can say it is not possible to place the wires in the conduit

4 0
3 years ago
A sewage lagoon that has a surface area of 10 ha and a depth of 1 m is receiving 8,640 m^3 /d of sewage containing 100 mg/L of b
Marysya12 [62]

Answer: Coefficient= 0.35 per day

Explanation:

To find the bio degradation reaction rate coefficient, we have

k= \frac{(Cin)(Qin)-(Cout)(Qout)}{(Clagoon)V}

Here, the C lagoon= 20 mg/L

Q in= Q out= 8640 m³/d

C in= 100 mg/L

C out= 20 mg/L

V= 10 ha* 1* 10

V= 10⁵ m³

So, k= \frac{8640*100-8640*20}{20*10^5}

k= 0.35 per day

6 0
3 years ago
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