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kicyunya [14]
3 years ago
11

The market for college textbooks is illustrated in the graph below. In the market for textbooks, the current price of a textbook

is $125. Which of the following statements best describes the current and future market conditions for textbooks?

Engineering
1 answer:
tresset_1 [31]3 years ago
7 0

Answer:

Option D is correct.

The market for textbooks has a shortage. There will be an upward pressure on price, which will cause quantity demanded to fall and quantity supplied to rise.

Explanation:

The complete question is attached to this solution.

Note that

- The quantity demanded is the negative sloping line in colour blue indicating that the quantity demanded increases as the price of the commodity (textbook) falls and the quantity demanded rises as the price of the textbook falls.

- The quantity supplied is the positive sloping line in colour red/orange indicating that the quantity supplied decreases as the price of the commodity (textbook) falls and the quantity supplied increases as the price of the textbook falls.

The quantity demanded and the quantity supplied balance each other and cross path at a point called the equilibrium point.

The price at this point is called the equilibrium price and the quantity at this point is the equilibrium quantity.

For this question, the equilibrium price = $150 and the equilibrium quantity that matches quantity demanded with quantity supplied = 500.

At prices greater than the equilibrium price, the quantity demanded falls and the quantity supplied increases, hence, there is a surplus of the commodity (textbook) as the quantity of textbooks supplied is way more than the quantity demanded and there is more than required textbooks.

At prices lower than the equilibrium price, the quantity demanded increases and the quantity supplied reduces, hence, there is a shortage of commodity (textbook) as all of the goods supplied are totally bought with extra demand remaining.

When there is a surplus or shortage, the market forces that are responsible for price fixing and quantity demanded work together to take the market back to equilibrium.

So, when the price is higher than equilibrium price and there is a surplus, the market works to reduce the price of the commodity so that quantity demanded can rise and quantity supplied can fall to counter this surplus.

When the price is lower than equilibrium price and there is a shortage, the market works to increase the price of the commodity so that quantity demanded can fall and quantity supplied can rise to counter this shortage.

The price of the textbook in the question, $125, is lower than the equilibrium price, $150, hence, there will be a shortage of textbooks because the quantity demanded, at this price, is higher than the quantity that will be supplied.

So, there is then a pressure on the price to rise back so that the quantity demanded reduces and the quantity supplied increases.

Hope this Helps!!!

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Let A→=(150iˆ+270jˆ) mm , B→=(300iˆ−450jˆ) mm , and C→=(−100iˆ−250jˆ) mm . Find scalars r and s, if possible, such that R→=rA→+s
ioda

Answer: r = 0.8081; s = -0.07071

Explanation:

A = (150i + 270j) mm

B = (300i - 450j) mm

C = (-100i - 250j) mm

R = rA + sB + C = 0i + 0j

R = r(150i + 270j) + s(300i - 450j) + (-100i - 250j) = 0i + 0j

R = (150r + 300s - 100)i + (270r - 450s - 250)j = 0i + 0j

Equating the i and j components;

150r + 300s - 100 = 0

270r - 450s - 250 = 0

150r + 300s = 100

270r - 450s = 250

solving simultaneously,

r = 0.8081 and s = -0.07071

QED!

5 0
3 years ago
The size of Carvins Cove water reservoir is 3.2 billion gallons. Approximately, 11 cfs of water is continuous withdrawn from thi
Zolol [24]

Answer:

471 days

Explanation:

Capacity of Carvins Cove water reservoir = 3.2 billion gallons i.e. 3.2 x 10˄9 gallons

As,  

1 gallon = 0.133 cubic feet (cf)

Therefore,  

Capacity of Carvins Cove water reservoir in cf  = 3.2 x 10˄9 x 0.133

                                                                         = 4.28 x 10˄8

 

Applying Mass balance i.e

Accumulation = Mass In - Mass out   (Eq. 01)

Here  

Mass In = 0.5 cfs

Mass out = 11 cfs

Putting values in (Eq. 01)

Accumulation  = 0.5 - 11

                         = - 10.5 cfs

 

Negative accumulation shows that reservoir is depleting i.e. at a rate of 10.5 cubic feet per second.

Converting depletion of reservoir in cubic feet per hour = 10.5 x 3600

                                                                                       = 37,800

 

Converting depletion of reservoir in cubic feet per day = 37, 800 x 24

                                                                                         = 907,200  

 

i.e. 907,200 cubic feet volume is being depleted in days = 1 day

1 cubic feet volume is being depleted in days = 1/907,200 day

4.28 x 10˄8 cubic feet volume will deplete in days  = (4.28 x 10˄8) x                    1/907,200

                                                                                 = 471 Days.

 

Hence in case of continuous drought reservoir will last for 471 days before dry-up.

8 0
2 years ago
Write a Nios II assembly program that reads binary data from the Slider Switches, SW11-0, on the DE2-115 Simulator, and display
Citrus2011 [14]

Algorithm of the Nios II assembly program.

  • Attain data for simulation from the  SW11-0, on the DE2-115 Simulator
  • The data will be  read from the switches in loop.
  • The decimal output is displayed using the seven-segment displays and done using the loop.
  • The program is ended by the user operating the SW1 switch

and

The decimal equivalent on the seven-segment displays HEX3-0 is

  • DE2-115
  • DE2-115_SW11
  • DE2-115_HEX3
  • DE2-115_HEX4
  • DE2-115_HEX5
  • DE2-115_HEX6
  • DE2-115_HEX7

<h3>The  Algorithm and decimal equivalent on the seven-segment displays HEX3-0</h3>

Generally,  the program will be written using a  cpulator simulator in order to attain best result.

We are to

  • Attain data for simulation from the  SW11-0, on the DE2-115 Simulator
  • The data will be  read from the switches in loop.
  • The decimal output is displayed using the seven-segment displays and done using the loop.
  • The program is ended by the user operating the SW1 switch

This will be the Algorithm of the Nios II assembly program .

Hence, the decimal equivalent on the seven-segment displays HEX3-0 is

  • DE2-115
  • DE2-115_SW11
  • DE2-115_HEX3
  • DE2-115_HEX4
  • DE2-115_HEX5
  • DE2-115_HEX6
  • DE2-115_HEX7

For more information on Algorithm

brainly.com/question/11623795

6 0
2 years ago
X cotx expansion using maclaurins theorem.
Lemur [1.5K]

It is to be noted that it is impossible to find the Maclaurin Expansion for F(x) = cotx.

<h3>What is Maclaurin Expansion?</h3>

The Maclaurin Expansion is a Taylor series that has been expanded around the reference point zero and has the formula f(x)=f(0)+f′. (0) 1! x+f″ (0) 2! x2+⋯+f[n](0)n!

<h3>What is the explanation for the above?</h3>

as indicated above, the Maclaurin infinite series expansion is given as:

F(x)=f(0)+f′. (0) 1! x+f″ (0) 2! x2+⋯+f[n](0)n!

If F(0) = Cot 0

F(0) = ∝ = 1/0

This is not definitive,

Hence, it is impossible to find the Maclaurin infinite series expansion for F(x) = cotx.

Learn more about Maclaurin Expansion at;
brainly.com/question/7846182
#SPJ1

4 0
1 year ago
Modify the one-dimensional continuity equation to include rainfall over the free surface
KonstantinChe [14]

The rainfall run off model  HEC-HMS is combined with river routing model. They are used for simulating the rainfall process.

Explanation:

The HEC - HMS rainfall model is used for simulating the rainfall runoff process. In this study the soil conservation service and curve number method is used to calculate the sub basin loss in basin module.

It provides various options for providing the rainfall distributions in the basin. It has the control specification module used to control the time interval for the simulations.

The one dimensional continuity equation is

бA / бT + бQ / бx= 0

3 0
2 years ago
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