Answer:
5.90 moles of ethane, C₂H₆, is burned in an excess of oxygen to produce 11.8 moles of CO₂.
Explanation:
To answer the question, we examine the chemical reaction as follows
2C₂H₆ ( g ) + 7O₂ ( g ) ⟶ 4CO₂ ( g ) + 6H₂O ( g )
From the chemical reaction it is seen that 2 moles of ethane, C₂H₆, is required to produce 4 moles of CO₂
This means that 1 mole of C₂H₆, is required to produce 2 moles of CO₂
Since we are asked to find out how many moles of CO 2 are produced when 5.90 moles of ethane is burned in an excess of oxygen and we already know that 1 mole of C₂H₆, is required to produce 2 moles of CO₂, we multiply both the 1 mole of C₂H₆ and the 2 moles of CO₂ by 5.90 to obtain;
(5.90 × 1 mole) of C₂H₆ is required to produce (5.90× 2 moles) of CO₂ or
5.90 moles of C₂H₆ is required to produce 11.8 moles of CO₂.
