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Leni [432]
3 years ago
11

"A pendulum is pulled back from its equilibrium (center) position and then released. When the pendulum bob is halfway between th

e high point and the low point in its swing, is the total energy kinetic energy, potential energy, or both
Physics
1 answer:
kumpel [21]3 years ago
3 0

Answer:

Option C, The total energy consists of half the original potential energy and half of the original potential energy converted to kinetic energy.

Explanation:

Complete question

A pendulum is pulled back from its equilibrium (center) position and then released. When the pendulum bob is halfway between the high point and the low point in its swing, is the total energy kinetic energy, potential energy, or both? Explain.

The total energy is kinetic energy only.

The total energy is potential energy only.

The total energy consists of half the original potential energy and half of the original potential energy converted to kinetic energy.

The total energy consists of one-fourth the original potential energy and three-fourths of the original potential energy converted to kinetic energy.

Solution

Total energy is the sum of kinetic energy and potential energy and as a pendulum moves back and forth, there is continuous transformation of energy from one form to the other form. i.e from kinetic energy to potential energy and vice versa.  

When the pendulum is released from some position, the potential energy  in it start converting into kinetic energy with the increase in speed of motion of pendulum bob

Hence, option C is correct

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Answer:

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Explanation:

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Technician A says that current is created in the stator windings of an alternator. Technician B says that the voltage regulator
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Answer:

Technician A and Technician B both are right.

Explanation:

In an AC alternator,  there are two windings

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Therefore, both technicians are right.

4 0
3 years ago
What causes competition among organisms?
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5 0
3 years ago
Which of the following is a nonferromagnetic material? (a) aluminum (b) iron (c) cobalt (d) gadolinium
ivolga24 [154]

Answer:

A

Explanation:

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5 0
3 years ago
A wire carrying a current of 26.9 A is bent into a circular arc with a radius of 0.6 cm that sweeps out 0.900 radians. What is t
melomori [17]

The magnetic field at the center of the arc is 4 × 10^(-4) T.

To find the answer, we need to know about the magnetic field due to a circular arc.

<h3>What's the mathematical expression of magnetic field at the center of a circular arc?</h3>
  • According to Biot savert's law, magnetic field at the center of a circular arc is
  • B=(μ₀ I/4π)× (arc/radius²)
  • As arc is given as angle × radius, so

        B=( μ₀I/4π)×(angle/radius)

<h3>What will be the magnetic field at the center of a circular arc, if the arc has current 26.9 A, radius 0.6 cm and angle 0.9 radian?</h3>

B=(μ₀ I/4π)× (0.9/0.006)

  = (10^(-7)× 26.9)× (0.9/0.006)

  = 4 × 10^(-4) T

Thus, we can conclude that the magnitude of magnetic field at the center of the circular arc is 4 × 10^(-4) T.

Learn more about the magnetic field of a circular arc here:

brainly.com/question/15259752

#SPJ4

5 0
2 years ago
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