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AVprozaik [17]
3 years ago
14

a 45 kg ice skater initially skating at a velocity of 3 m/s speeds up to a velocity of 5 m/s. calculate the difference in the ma

gnitude of momentum of the skater.
Physics
2 answers:
ad-work [718]3 years ago
4 0

Answer: 90 kgm/s

Explanation:

The momentum (linear momentum) p is given by the following equation:

p=m.V

Where:

m=45 kg is the mass of the skater

V is the velocity

In this situation the skater has two values of momentum:

Initial momentum: p_{1}=m.V_{1}

Final momentum: p_{2}=m.V_{2}

Where:

V_{1}=3 m/s

V_{1}=5 m/s

So, if we want to calculate the difference in the magnitude of the skater's momentum, we have to write the following equation(assuming the mass of the skater remains constant):

p=p_{2}-p_{1}=m.V_{2}-m.V_{1}

p=m(V_{2}-V_{1})

p=45 kg(5 m/s - 3 m/s)

Finally:

p=90 kgm/s

ExtremeBDS [4]3 years ago
4 0

Answer: 90m

Explanation:I hope this helps

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