Answer: I think it’s point cd and line cd
Explanation:
Answer:
σ = ±708 nC/m²
Q = ±177 nC
Explanation:
given data
Side of copper plate L = 50 cm
Electric field, E = 80 kN/C
solution
we get here Charge density,σ that is express as
σ = E x ε₀ ....................1
here ε₀ is Permittivity of free space that is 8.85 x 10⁻¹² C²/Nm²
so put value in eq1we get
σ = 80 x 10³ x 8.85 x 10⁻¹²
σ = 708 x 10⁻⁹ C/m²
σ = 708 nC/m²
and
now we get here total change on each faces
Q = σ A ...............2
Q = 708 x 10⁻⁹ x (0.50)²
Q = 177 nC
Go neutreal, turn blinkers on, then brake onto the side of the road.
The problem describes the relationship of "bulb a" and "bulb b" to be in connected in series. When the switch is open then no current can flow, on the other hand, when it is closed, current will pass through.
When only "bulb a" is connected to the battery then more current is flowing to "bulb a" causing it to be bright.
Closing the switch would mean that "bulb b" is already included in the circuit and the battery will push small current to flow around the whole circuit. The more bulbs are connected, the harder for the current to flow because the resistance will be very high.
So the light of "bulb a" will be dimmer.
Answer:
a)
b)
c)
The estimate is low.
Explanation:
a) Using the energy conservation we have:
we have kinetic energy intially and gravitational potential energy at the maximum height.
b) We can use the equation of the gravitational force
(1)
We have that:
(2)
at the surface G will be:
Now the equation of an object at a distance x from the surface.
is:
Using that dv/dt is vdx/dt and integrating in both sides we have:
c) The difference is:
So the percent difference will be:
The estimate is low.
I hope it helps you!
