-- We know that the y-component of acceleration is the derivative of the y-component of velocity.
-- We know that the y-component of velocity is the derivative of the y-component of position.
-- We're given the y-component of position as a function of time.
So, finding the velocity and acceleration is simply a matter of differentiating the position function ... twice.
Now, the position function may look big and ugly in the picture. But with the exception of 't' , everything else in the formula is constants, so we don't even need any fancy processes of differentiation. The toughest part of this is going to be trying to write it out, given the text-formatting capabilities of the wonderful envelope-pushing website we're working on here.
From the picture . . . . . y (t) = (1/2) (a₀ - g) t² - (a₀ / 30t₀⁴ ) t⁶
First derivative . . . y' (t) = (a₀ - g) t - 6 (a₀ / 30t₀⁴ ) t⁵ = (a₀ - g) t - (a₀ / 5t₀⁴ ) t⁵
and there's your acceleration . . . /\ . That's the one you're supposed to graph.
a₀ is the acceleration due to the model rocket engine thrust combined with the mass of the model rocket 'g' is the acceleration of gravity ... 9.8 m/s² or 32.2 ft/sec² t₀ is how long the model rocket engine burns
Pick, or look up, some reasonable figures for a₀ and t₀ and you're in business.
The big name in model rocketry is Estes. Their website will give you all the real numbers for thrust and burn-time of their engines, if you want to follow it that far.
